Results 1 to 3 of 3

Thread: [RESOLVED] Break-even quadratic equation

  1. #1

    Thread Starter
    Lively Member
    Join Date
    Jan 2007
    Posts
    121

    Resolved [RESOLVED] Break-even quadratic equation

    Hey everybody

    I have a problem that I am facing trouble solving regarding break-even

    I got the total cost and the revenue functions below where x represents the number of production units and I need to find the number of units to make in order to break even

    C(x) = 6300 + 80x + x^2
    R(x) = 240x

    My solution:

    B.E(x) = 240x = 6300 + 80x + x^2
    x^2 - 232x + 6300 = 0

    Now I am supposed to find x, i tried by factoring but I never really found a solution with no fractions. Tried the quadratic formula didnt work either and i got different answers. I used an online quadratic equation calculator and it gave me different set of answers.

    Now i am totally confused and frustrated as I am trying to find a solution, help would be appreciated

    thanks in advance
    Kalogerus Productions (K-Pro)

  2. #2
    Only Slightly Obsessive jemidiah's Avatar
    Join Date
    Apr 2002
    Posts
    2,431

    Re: Break-even quadratic equation

    You subtracted by 8 instead of 80.


    I'd help with the rest but you seem to know how it's done from there.
    The time you enjoy wasting is not wasted time.
    Bertrand Russell

    <- Remember to rate posts you find helpful.

  3. #3

    Thread Starter
    Lively Member
    Join Date
    Jan 2007
    Posts
    121

    Re: Break-even quadratic equation

    WOW lol

    thanks alot,,, too much math for one day i guess lmfao
    Kalogerus Productions (K-Pro)

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •  



Click Here to Expand Forum to Full Width