Anti derivative (16-2x)^0.5

[jeremydave]

Hi, anybody here know how to anti derivative of this formula, (16-2x)^0.5. Please help me with working, thank. Any type of working are welcome, thank for your help.

[jeremydave]

I have found how to anti derivative this formula (16-2x)^0.5
2/3 divide by -2 (16-2x)^1/2+1 Anyway thk. -2 is the differential of 2x.

[Mattywoo2]

INT (16-2x)^0.5 dx

Let 16-2x = u, so du/dx = -2

Our integral becomes

INT -1/2 (u)^0.5 du = -1/3 (u)^1.5 + C = -1/3 (16-2x)^1.5 + C

[jeremydave]

oh, it work out like this, your method is good, thk Mattywoo2. Thk for reminding me that I forgot to add "C" in the equation.