Ok. Some questions about Public Functions.

[Apollo]

In creating a function, what must I do?

Do I need to write

Public Function MYFACTORIAL(number as integer, otherone as integer, lastone as integer)

number = otherone * lastone

end function

Or what? Someone show me the correct syntax for a public function. Thank you, goodbye.

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"I'm carrying a Geometry book, but I'm not in Geometry...it's crazy...crazy man!"

[QWERTY]

Hope this will work:

Public Function Factorial (anotherone as integer, lastone as integer)
    Factorial=AnotherOne * LastOne
End Function

To call this function and calculate value for Number do:

Number=Factorial (AnotherOne, LastOne)

------------------
Visual Basic Programmer
-----------------
PolComSoft
You will hear a lot about it.

[Apollo]

Well, would the same go for a for-next statement?

Public Function MYFACTORIAL(numberin as Integer, newnumber as integer,counter as integer)

MYFACTORIAL = For counter = 1 to numberin

newnumber = newnumber * counter

next

end function

Would it?

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"I'm carrying a Geometry book, but I'm not in Geometry...it's crazy...crazy man!"

[Serge]

Not exactly:

Public Function MyFactorial(NumberIn As Integer)
    Dim i As Integer
    
    For i = 1 To NumberIn
        MyFactorial = MyFactorial + NumberIn
    Next
End Function

Example: MsgBox MyFactorial 10

The result would 55.

Regards,

------------------

Serge

Software Developer
[email protected]
[email protected]
ICQ#: 51055819




[This message has been edited by Serge (edited 11-04-1999).]

[QWERTY]

Public Function Factorial(numberin As Integer)
    dim Counter as Integer
    Factorial = 1
    For counter = 1 To numberin
        Factorial = Factorial * counter
    Next counter
End Function

To call this function

Number=factorial(NumberIn)

Hope this what You are looking for

------------------
Visual Basic Programmer
-----------------
PolComSoft
You will hear a lot about it.

[This message has been edited by QWERTY (edited 11-04-1999).]

[QWERTY]

Serge's method will only work for addition and substraction because if you use multiplication or division or something like that you will always have Factorial value of 0. On the other hand my method won't work for addition and substraction
------------------
Visual Basic Programmer
-----------------
PolComSoft
You will hear a lot about it.


[This message has been edited by QWERTY (edited 11-04-1999).]