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Thread: process.start problem

  1. #1

    Thread Starter
    Lively Member
    Join Date
    Aug 2001
    Posts
    77

    process.start problem

    I would like to call a .NET executable file in a windows service at certain intervals of time. The following is the code snippet, I put in. I am not receiving any error in my error handling routine (as it writes as a log entry). But my problem is, the respective application doesn't popup on screen and get visible. I desperately need the application to be visible when it does some work (just to know basically the status and progress of the process it is doing). I copied calc.exe into the root to test it. But I didn't test with anything else. Can anybody help me please.

    'first method
    'Dim proc As Process = Process.Start("c:\calc.exe")

    'second method
    'Dim startInfo As New ProcessStartInfo("c:\calc.exe")
    'startInfo.CreateNoWindow = False
    'startInfo.WindowStyle = ProcessWindowStyle.Normal
    'Process.Start(startInfo)

    'third method
    'Shell("c:\calc.exe"), AppWinStyle.NormalFocus, False)

  2. #2
    I wonder how many charact
    Join Date
    Feb 2001
    Location
    Savage, MN, USA
    Posts
    3,704
    I haven't had much luck with showing windows spawned by Process either, but there's more to it than the simple interface we've been given.

    Obviously, a user must be logged in and looking at their desktop to see any GUI...

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