|
-
Aug 2nd, 2004, 11:17 PM
#1
Thread Starter
Lively Member
process.start problem
I would like to call a .NET executable file in a windows service at certain intervals of time. The following is the code snippet, I put in. I am not receiving any error in my error handling routine (as it writes as a log entry). But my problem is, the respective application doesn't popup on screen and get visible. I desperately need the application to be visible when it does some work (just to know basically the status and progress of the process it is doing). I copied calc.exe into the root to test it. But I didn't test with anything else. Can anybody help me please.
'first method
'Dim proc As Process = Process.Start("c:\calc.exe")
'second method
'Dim startInfo As New ProcessStartInfo("c:\calc.exe")
'startInfo.CreateNoWindow = False
'startInfo.WindowStyle = ProcessWindowStyle.Normal
'Process.Start(startInfo)
'third method
'Shell("c:\calc.exe"), AppWinStyle.NormalFocus, False)
-
Aug 3rd, 2004, 11:06 AM
#2
I wonder how many charact
I haven't had much luck with showing windows spawned by Process either, but there's more to it than the simple interface we've been given.
Obviously, a user must be logged in and looking at their desktop to see any GUI...
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
|
Click Here to Expand Forum to Full Width
|