C#-Base64 Encoding and Decoding

[Sgt-Peppa]

To encode a string

public string base64Encode(string data)
{
    try
    {
        byte[] encData_byte = new byte[data.Length];
        encData_byte = System.Text.Encoding.UTF8.GetBytes(data);    
        string encodedData = Convert.ToBase64String(encData_byte);
        return encodedData;
    }
    catch(Exception e)
    {
        throw new Exception("Error in base64Encode" + e.Message);
    }
}

and to decode

public string base64Decode(string data)
{
    try
    {
        System.Text.UTF8Encoding encoder = new System.Text.UTF8Encoding();  
        System.Text.Decoder utf8Decode = encoder.GetDecoder();
    
        byte[] todecode_byte = Convert.FromBase64String(data);
        int charCount = utf8Decode.GetCharCount(todecode_byte, 0, todecode_byte.Length);    
        char[] decoded_char = new char[charCount];
        utf8Decode.GetChars(todecode_byte, 0, todecode_byte.Length, decoded_char, 0);                   
        string result = new String(decoded_char);
        return result;
    }
    catch(Exception e)
    {
        throw new Exception("Error in base64Decode" + e.Message);
    }
}

Hope that saves some time,

Stephan

[SugarDaddy420]

No offense, but there's certainly a more elegant solution. I'm not sure why you're catching a specific exception just to throw a more general one either.

public string Encode(string str)
{
   byte[] encbuff = System.Text.Encoding.UTF8.GetBytes(str);
   return Convert.ToBase64String(encbuff);
}
public string Decode(string str)
{
   byte[] decbuff = Convert.FromBase64String(str);
   return System.Text.Encoding.UTF8.GetString(decbuff);
}

[SugarDaddy420]

Pardon me. I now understand why you were throwing the exception. When an exception occurs within a function, it does not pass it out to the containing function that made the call. You have to throw it back yourself. Nicely done.

[axion_sa]

The following is a better way of bubbling exceptions. It's not entirely necessary in this situation though

try
{
    // Code here
}
catch (Exception ex)
{
    throw new Exception("Error in base64Decode: " + e.Message, ex);
}

This way, the caller will have access to the original exception information (stack trace et al).

[mj12]

Originally Posted by Sgt-Peppa

To encode a string

public string base64Encode(string data)
{
    try
    {
        byte[] encData_byte = new byte[data.Length];
        encData_byte = System.Text.Encoding.UTF8.GetBytes(data);    
        string encodedData = Convert.ToBase64String(encData_byte);
        return encodedData;
    }
    catch(Exception e)
    {
        throw new Exception("Error in base64Encode" + e.Message);
    }
}

and to decode

public string base64Decode(string data)
{
    try
    {
        System.Text.UTF8Encoding encoder = new System.Text.UTF8Encoding();  
        System.Text.Decoder utf8Decode = encoder.GetDecoder();
    
        byte[] todecode_byte = Convert.FromBase64String(data);
        int charCount = utf8Decode.GetCharCount(todecode_byte, 0, todecode_byte.Length);    
        char[] decoded_char = new char[charCount];
        utf8Decode.GetChars(todecode_byte, 0, todecode_byte.Length, decoded_char, 0);                   
        string result = new String(decoded_char);
        return result;
    }
    catch(Exception e)
    {
        throw new Exception("Error in base64Decode" + e.Message);
    }
}

Hope that saves some time,

Stephan

Indeed it does Stephan! Short, sweet and right to the meat of it. Thanks for sharing it, m8y!

[Chimp]

Originally Posted by SugarDaddy420

Pardon me. I now understand why you were throwing the exception. When an exception occurs within a function, it does not pass it out to the containing function that made the call. You have to throw it back yourself. Nicely done.

Yes it does. What do you mean it does not pass it out to the containing function??