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  1. #1

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    Label : recover the value of each digit

    Hello friends,

    I need advice to analyze a label that contains a sequence of 4 numbers 0 or 1. (ex: 0101 or 1101 etc.)
    Each number corresponds to a state.
    Is it possible to recover the value of each digit?

    For example, if the first digit is a 0 then label1.text = "0"
    If the second digit is a 1 then label2.text = "1" etc ...

    Thanks for your help

  2. #2
    Lively Member Goggy's Avatar
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    Re: Label : recover the value of each digit

    This would one way of doing it...

    Code:
      Dim Source As String = "a0100110101"
    
    
            For Each C As Char In Source
                Select Case True
                    Case Asc(C) = 48
                        Debug.Print("An 0")
                    Case Asc(C) = 49
                        Debug.Print("An 1")
                    Case Else
                        Debug.Print("Not a 0 or and 1")
                End Select
            Next
    Utterly useless, but always willing to help

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  3. #3

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    Re: Label : recover the value of each digit

    Quote Originally Posted by Goggy View Post
    This would one way of doing it...

    Code:
      Dim Source As String = "a0100110101"
    
    
            For Each C As Char In Source
                Select Case True
                    Case Asc(C) = 48
                        Debug.Print("An 0")
                    Case Asc(C) = 49
                        Debug.Print("An 1")
                    Case Else
                        Debug.Print("Not a 0 or and 1")
                End Select
            Next

    Thank you for your answer, I start VB and I can not understand your code can you give me an explanation?

  4. #4
    Lively Member Goggy's Avatar
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    Re: Label : recover the value of each digit

    What happens is,

    The source would be your label that contains the value you want to check.

    The for loop takes every character in the value and checks if its a 0 a 1 or something else...

    asc(c) transforms a charactor to its ascii value... (http://www.asciitable.com/)
    Utterly useless, but always willing to help

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  5. #5

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    Re: Label : recover the value of each digit

    I do not want to check if the source label contains 0 or 1 because it is a certainty.
    On the other hand I wish to separate the 4 digits to analyze them

  6. #6
    Lively Member Goggy's Avatar
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    Re: Label : recover the value of each digit

    It does that for you.... it breaks down the source in its characters and checks if the character is a 0, a 1 or something else...
    Utterly useless, but always willing to help

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  7. #7
    .NUT jmcilhinney's Avatar
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    Re: Label : recover the value of each digit

    First things first, you should not be checking any Label. Labels are not for data storage. Their purpose is to display something to the user, not to store it. Whatever is being displayed in that Label must have been put there from somewhere by your code and it's that original that you should be using. You should be storing your data in a variable somewhere and displaying the contents of that variable in the Label. When you want to use the data, you use the variable, not the Label. If the data ever changes, you change the variable and then display the variable in the Label.

    As for your problem, you should treat the binary String as though it was an array of Char values, i.e. access each Char by index. That way, you can put your four destination Labels in an array and then use a For loop to access the Char and the corresponding Label by index. There's no need to actually test anything because all you're doing is displaying the individual Chars. It's sill to say if the Char is a 1 then display a 1 and if it's a 0 then display a 0 because the end result is you display the Char, so do that.
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  8. #8

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    Re: Label : recover the value of each digit

    Ok you're right I'll try to find other solutions

  9. #9
    Lively Member Goggy's Avatar
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    Re: Label : recover the value of each digit

    This is an other approach;

    Code:
    Dim Source As String = "a0100110101"
    
            For I As Integer = 0 To Source.Length - 1
                If Source(I) = "0" Then
                    ' Do something 
                ElseIf Source(I) = "1" Then
                    ' Do something
                Else
                    ' Do Nothing...
                End If
            Next
    Last edited by Goggy; Dec 19th, 2017 at 11:04 AM.
    Utterly useless, but always willing to help

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  10. #10
    Powered By Medtronic dbasnett's Avatar
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    Re: Label : recover the value of each digit

    Here are some ideas using an enumeration with a flags attribute and convert for binary string conversion.

    Code:
    Public Class Form1
    
        <Flags> Enum SomeStates As Integer
            'note that each state is represented by one bit
            a = 1 << 0
            b = 1 << 1
            c = 1 << 2
            d = 1 << 3
            ' ... etc.
            last = 1 << 31
        End Enum
    
        Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
            Dim foo As SomeStates = SomeStates.a Or SomeStates.b Or SomeStates.d Or SomeStates.last
            If foo.HasFlag(SomeStates.b) Then
                Stop
            End If
            Dim s As String
            s = foo.ToString
            Debug.WriteLine(s)
            s = DirectCast(foo, Integer).ToString
            Debug.WriteLine(s)
    
            Dim states As String = "1001"
            foo = DirectCast(Convert.ToInt32(states, 2), SomeStates)
            Debug.WriteLine(foo)
    
            foo = foo Or SomeStates.last
            s = Convert.ToString(foo, 2)
            Debug.WriteLine(s)
        End Sub
    End Class
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  11. #11

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    Re: Label : recover the value of each digit

    Thanks again for your answers

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