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Thread: [RESOLVED] MySQL stored procedure, order by with condition

  1. #1

    Thread Starter
    PowerPoster make me rain's Avatar
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    Resolved [RESOLVED] MySQL stored procedure, order by with condition

    Code:
    SELECT C1,C2,C3 FROM Tbl
    ORDER BY
    IF (VariableA > VariableB , C1 DESC , C1 ASC) ;
    
    -- Here VariableA and VariableB are the variables declared in 
    -- Stored procedure
    but this is syntax error how can i do it
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  2. #2
    PowerPoster techgnome's Avatar
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    Re: MySQL stored procedure, order by with condition

    I don't think it's that simple... you could swap between two fields/values, but they'd have the same DESC/ASC sort... you're looking to swap the sort order, which you can't just arbitrarily switch like that. What you'll probably need to do is have TWO select statements, exactly the same, but with the different sort orders, and then call one or the other based on your variables:
    Code:
    If VarA > VarB
       SELECT C1,C2,C3 FROM Tbl
       ORDER BY C1 DESC
    else
        SELECT C1,C2,C3 FROM Tbl
        ORDER BY C1 ASC
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  3. #3
    Super Moderator si_the_geek's Avatar
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    Re: MySQL stored procedure, order by with condition

    This may work:
    Code:
    ORDER BY IF (VariableA > VariableB , -1 * C1, C1) ASC ;

  4. #4

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    Re: MySQL stored procedure, order by with condition

    Superb
    thanks for the help Tech and Geek
    The averted nuclear war
    My notes:

    PrOtect your PC. MSDN Functions .OOP LINUX forum
    .LINQ LINQ videous
    If some one helps you please rate them with out fail , forum doesn't expects any thing other than this

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