thnaks for reply
see my code
Code:
$result = mysql_query("SELECT * FROM login where LoginID= '$username' and Password1= '$password' ");
if($result)
{
echo "success";
}
else
{
echo "There were no results for your search";
}
also
Code:
<script type="text/javascript">
$(document).ready(function() {
$("#login").click(function() {
var action = $("#form1").attr('action');
var form_data = {
username: $("#username").val(),
password: $("#password").val(),
is_ajax: 1
};
$.ajax({
type: "POST",
url: action,
data: form_data,
success: function(response)
{
if(response == 'success')
$("#form1").slideUp('slow', function() {
$("#message").html("<p class='success'>You have logged in successfully!</p>");
});
else
{
// echo response;
$("#message").html("<p class='error'>Invalid username and/or password.</p>");
}
}
});
return false;
});
});
</script>
if i input wron password it also show me message
You have logged in successfully ..please mention if need full code