I'm wonder if I had a code, say 9319, how could I get every possible combination of it, IE 9319, 9139, etc..
Cheers
Icyculyr
I'm wonder if I had a code, say 9319, how could I get every possible combination of it, IE 9319, 9139, etc..
Cheers
Icyculyr
Nested loops would do this.
Code:For firstNumericDigit as integer = 0 to 9 For secondNumericDigit as integer = 0 to 3 ' .. Other loops here ' .. linkage of variable values and output here
Please rate this post if it was useful for you!
Please try to search before creating a new post,
Please format code using [ code ][ /code ], and
Post sample code, error details & problem details
Thanks, it's not quite what I mean though, I want all possible combinations of specific 4 digit code, IE, every possible combination containing the numbers 9319, etc.. not every possible 4 digit combination
Cheers
Icyculyr
Well so far i have come up with this.
vb Code:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim A As Integer Dim B As Integer Dim C As Integer Dim D As Integer A = 1 B = 2 C = 3 D = 4 Label1.Text = A & B & C & D Label2.Text = A & B & D & C Label3.Text = A & C & B & D Label4.Text = A & C & D & B Label5.Text = A & D & B & C Label6.Text = A & D & C & B Label7.Text = B & A & C & D Label8.Text = B & A & D & C Label9.Text = B & C & A & D ' Etc Etc Etc End Sub
Now the thing I am not sure on, which you might be able to do is take the first number inside of a textbox say, and put that as A, and the second as B etc.
So A = Textbox1.text.(first) or what ever.
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
I had help on this, so I can not take all the credit.
But here you go.
vb Code:
A = TextBox1.Text.Substring(0, 1) B = TextBox1.Text.Substring(1, 1) C = TextBox1.Text.Substring(2, 1) D = TextBox1.Text.Substring(3, 1)
I have to give thanks to Mr Ludwig
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
Something else, you will get an error if you do not have 4 numbers. Plus you will get an error if you put letters inside. So.....
All of that into an If statement.
vb Code:
If Textbox1.Text.Length = 4 Then ' Do the code already given Else MsgBox("TextBox does not contain 4 digits!") End If
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
I love it - nice challenge!Good question that! Ok I *think* this works, appears to from a quick glance but I'll leave you to check all the combinations are there:
Code:Public Class Form1 Private _temporaryOutputString As String Private Sub Form1_Load(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles MyBase.Load Dim numericCodeOutputArrayList As New ArrayList Dim numericCodeInitArray(3) As String numericCodeInitArray(0) = "1" '"9" numericCodeInitArray(1) = "2" '"3" numericCodeInitArray(2) = "3" '"1" numericCodeInitArray(3) = "4" '"9" numericCodeOutputArrayList.Add(numericCodeInitArray(0)) numericCodeOutputArrayList.Add(numericCodeInitArray(1)) numericCodeOutputArrayList.Add(numericCodeInitArray(2)) numericCodeOutputArrayList.Add(numericCodeInitArray(3)) Dim firstOutputElementText As String = "" Dim secondOutputElementText As String = "" Dim thirdOutputElementText As String = "" For repositionFirstIndex As Integer = 0 To 3 For repositionSecondIndex As Integer = 0 To 2 For repositionThirdIndex As Integer = 0 To 1 OutputCurrentNumericCode(numericCodeOutputArrayList) thirdOutputElementText = numericCodeOutputArrayList.Item(2) numericCodeOutputArrayList.RemoveAt(2) numericCodeOutputArrayList.Add(thirdOutputElementText) Next repositionThirdIndex secondOutputElementText = numericCodeOutputArrayList.Item(1) numericCodeOutputArrayList.RemoveAt(1) numericCodeOutputArrayList.Add(secondOutputElementText) Next repositionSecondIndex firstOutputElementText = numericCodeOutputArrayList.Item(0) numericCodeOutputArrayList.RemoveAt(0) numericCodeOutputArrayList.Add(firstOutputElementText) Next repositionFirstIndex End Sub Private Sub OutputCurrentNumericCodeToTextbox(ByRef numericCodeArrayList As ArrayList) _temporaryOutputString = numericCodeArrayList.Item(0) _temporaryOutputString &= numericCodeArrayList.Item(1) _temporaryOutputString &= numericCodeArrayList.Item(2) _temporaryOutputString &= numericCodeArrayList.Item(3) _temporaryOutputString &= Environment.NewLine TextBox1.Text &= _temporaryOutputString End Sub End Class
Last edited by alex_read; May 6th, 2008 at 05:15 AM.
Please rate this post if it was useful for you!
Please try to search before creating a new post,
Please format code using [ code ][ /code ], and
Post sample code, error details & problem details
Look in VB.Net code bank. I remember seeing a thread on creating unique combinations (permutation) there. With just 4 digits, it's OK to hard code it the way you do now, but imagine if you have 10 or more digits, you will not want to hard code it then![]()
But he doesn't have 10 digits, I see where you are going with this true it would be a nightmare to hardcode all combinations of a 10 digits.
But he only wants 4, which is only a 2 min job to hardcode all those combinations.
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
Didn't I say it's OK to hard code with only 4 digits?Originally Posted by Lerroy_Jenkins
![]()
Yes
![]()
I am just stuck on trying to work out how to stop an error being thrown up if the user puts in letters. My code works with Numbers.
And as for Alex's code..that went right over my head!
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
How about using simple If's statement to check for the string.length first?Originally Posted by Lerroy_Jenkins
Code:If userInput.Length >= 5 Then 'Do something Else MessageBox.Show("Input must be at least 5 character long!") End If
Originally Posted by Lerroy_Jenkins
This is what I have said a few posts ago, so I am checking that.
But all of my code only works for numbers, not letters.
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
Ok ok I guess I can put in some comments, sorry!
I was storing the numbers in an arraylist as it has a remove() method. So 1st time it runs, the value is:
1234
After I print this, I store, then drop the 1st number using that removeat() method, so I get this:
234
and then I add that number to the end, so I get this:
2341
The loop runs round this procedure 4 times, each time dropping the 1st character, and appending it to the end to give:
1234
2341
3412
4123
The inner loops are doing the same thing, just on different characters - the 1st loop looks at the 2st character and worries about replacing that one, the 2nd loop does the same for the 2nd character out of the 4, and so-on if that makes sense...![]()
![]()
![]()
Please rate this post if it was useful for you!
Please try to search before creating a new post,
Please format code using [ code ][ /code ], and
Post sample code, error details & problem details
That is very clever! I understand it a little better now.
I like my code better though.... Its simple... Just like me
![]()
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
Thanks![]()
Quite a challenge and took a little while though! I noticed in the original, you had 2 of the same number there 9319 so the sample above will throw duplicates up (I was testing 1234 to make things easier in that one above). Here is a second sample for your scenario specifically, which removes the duplicates which the two 9 values create:
Code:Public Class Form1 Private _temporaryOutputString As String Private _temporaryOutputArrayList As ArrayList Private Sub Form1_Load(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles MyBase.Load Dim numericCodeOutputArrayList As New ArrayList Dim numericCodeInitArray(3) As String numericCodeInitArray(0) = "9" numericCodeInitArray(1) = "3" numericCodeInitArray(2) = "1" numericCodeInitArray(3) = "9" numericCodeOutputArrayList.Add(numericCodeInitArray(0)) numericCodeOutputArrayList.Add(numericCodeInitArray(1)) numericCodeOutputArrayList.Add(numericCodeInitArray(2)) numericCodeOutputArrayList.Add(numericCodeInitArray(3)) Dim firstOutputElementText As String = "" Dim secondOutputElementText As String = "" Dim thirdOutputElementText As String = "" _temporaryOutputArrayList = New ArrayList For repositionFirstIndex As Integer = 0 To 3 For repositionSecondIndex As Integer = 0 To 2 For repositionThirdIndex As Integer = 0 To 1 StoreCurrentNumericCode(numericCodeOutputArrayList) thirdOutputElementText = numericCodeOutputArrayList.Item(2) numericCodeOutputArrayList.RemoveAt(2) numericCodeOutputArrayList.Add(thirdOutputElementText) Next repositionThirdIndex secondOutputElementText = numericCodeOutputArrayList.Item(1) numericCodeOutputArrayList.RemoveAt(1) numericCodeOutputArrayList.Add(secondOutputElementText) Next repositionSecondIndex firstOutputElementText = numericCodeOutputArrayList.Item(0) numericCodeOutputArrayList.RemoveAt(0) numericCodeOutputArrayList.Add(firstOutputElementText) Next repositionFirstIndex RemoveNumericCodeDuplicates(_temporaryOutputArrayList) OutputUniqueNumericCodes(_temporaryOutputArrayList) End Sub Private Sub StoreCurrentNumericCode(ByRef numericCodeArrayList As ArrayList) _temporaryOutputString = numericCodeArrayList.Item(0) _temporaryOutputString &= numericCodeArrayList.Item(1) _temporaryOutputString &= numericCodeArrayList.Item(2) _temporaryOutputString &= numericCodeArrayList.Item(3) _temporaryOutputString &= Environment.NewLine _temporaryOutputArrayList.Add(_temporaryOutputString) End Sub Private Sub RemoveNumericCodeDuplicates(ByRef storedNumericCodeArrayList As ArrayList) Dim currentlyEvaluatedElementText As String = "" Dim IsReadLoopOfArraylistComplete As Boolean = False Dim IsDuplicateRemovalLoopOfArraylistComplete As Boolean = False Dim storedNumericCodeElementIndex As Integer = 0 Dim duplicateSearchElementIndex As Integer = 0 Do Until storedNumericCodeElementIndex >= storedNumericCodeArrayList.Count currentlyEvaluatedElementText = _ storedNumericCodeArrayList(storedNumericCodeElementIndex) duplicateSearchElementIndex = storedNumericCodeElementIndex + 1 If currentlyEvaluatedElementText = 9139 Then Dim i As Integer = 1 End If Do Until duplicateSearchElementIndex >= storedNumericCodeArrayList.Count If (storedNumericCodeArrayList(duplicateSearchElementIndex) = _ currentlyEvaluatedElementText) Then storedNumericCodeArrayList.RemoveAt(duplicateSearchElementIndex) duplicateSearchElementIndex = duplicateSearchElementIndex - 1 If Not (storedNumericCodeElementIndex = 0) Then storedNumericCodeElementIndex = storedNumericCodeElementIndex - 1 End If End If duplicateSearchElementIndex += 1 Loop storedNumericCodeElementIndex += 1 Loop End Sub Private Sub OutputUniqueNumericCodes(ByRef storedNumericCodeArrayList As ArrayList) For storedNumericCodeElementIndex = 0 To storedNumericCodeArrayList.Count - 1 TextBox1.Text &= storedNumericCodeArrayList(storedNumericCodeElementIndex) 'TextBox1.Text &= Environment.NewLine Next storedNumericCodeElementIndex End Sub End Class
Please rate this post if it was useful for you!
Please try to search before creating a new post,
Please format code using [ code ][ /code ], and
Post sample code, error details & problem details
I had help on a different part of this code from "Shuja Ali".
But here is the end piece, this will give you all possible combinations for a 4 digit number.
vb Code:
Public Class Form1 Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim A As Integer Dim B As Integer Dim C As Integer Dim D As Integer If IsNumeric(TextBox1.Text) Then If TextBox1.Text.Length = 4 Then A = TextBox1.Text.Substring(0, 1) B = TextBox1.Text.Substring(1, 1) C = TextBox1.Text.Substring(2, 1) D = TextBox1.Text.Substring(3, 1) Label1.Text = A & B & C & D Label2.Text = A & B & D & C Label3.Text = A & C & B & D Label4.Text = A & C & D & B Label5.Text = A & D & B & C Label6.Text = A & D & C & B Label7.Text = B & A & C & D Label8.Text = B & A & D & C Label9.Text = B & C & A & D Label10.Text = B & C & D & A Label11.Text = B & D & A & C Label12.Text = B & D & C & A Label13.Text = C & A & B & D Label14.Text = C & A & D & B Label15.Text = C & B & A & D Label16.Text = C & B & D & A Label17.Text = C & D & A & B Label18.Text = C & D & B & A Label19.Text = D & A & B & C Label20.Text = D & A & C & B Label21.Text = D & B & A & C Label22.Text = D & B & C & A Label23.Text = D & C & A & B Label24.Text = D & C & B & A Else MsgBox("TextBox does not contain 4 Numbers!") End If Else MsgBox("TextBox does not contain 4 Numbers!") End If End Sub Public Function IsNumeric(ByVal inputString As String) As Boolean Dim _isNumber As System.Text.RegularExpressions.Regex = New _ System.Text.RegularExpressions.Regex("(^[-+]?\d+(,?\d*)*\.?\d*([Ee][-+]\d*)?$)|(^[-+]?\d?(,?\d*)*\.\d+([Ee][-+]\d*)?$)") Return _isNumber.Match(inputString).Success End Function End Class
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
So, in other words, you want to restrict the user to input only numeric values, right? If it's the case, there are various methods you can implement.Originally Posted by Lerroy_Jenkins
1. Use a NumericUpDown control instead of a TextBox. This is by far the easiest method because the control handles the filtering for you automatically, you don't have top write any additional code.
2. If you MUST use a TextBox, then you should handle the KeyPress event of the textbox and check to see if the inputted KeyChar is numeric. If it's not, you cancel the event. Search the forum for "numeric textbox" and you'll find some example.
3. Depending on what value type you're expecting to get from the user, use the TryParse method of that Type (i.e Integer.TryParse, Double.TryParse...), and if the TryParse returns false, you know that it's not a valid number.
I don't know about you guys but I had the same question for a homework assignment when I took a VB.Net course about 4 years ago. You may have done his homework for him.![]()
KrisSiegel.com - My Personal Website with my blog and portfolio
Don't Forget to Rate Posts!
Free Icons: FamFamFam, VBCorner, VBAccelerator
Useful Links: System.Security.SecureString Managed DPAPI Overview Part 1 Managed DPAPI Overview Part 2 MSDN, MSDN2, Comparing the Timer Classes
Drat. I wondered that, but I thought no - couldn't be as that was a hard one. Ohh well got caught out that time then.![]()
![]()
![]()
Please rate this post if it was useful for you!
Please try to search before creating a new post,
Please format code using [ code ][ /code ], and
Post sample code, error details & problem details
This is pretty interesting. Here's what I came up with. It's totally dynamic, so it works with any number you input. But it is not the best method, only a quick and dirty one. It works on this principle:
Permute: 1234
Start with 1.
Take 2, and place it at every possible position in 1: 21, 12
Take 3, and place it at every possible position in the previous numbers: 321, 231, 213, 312, 132, 123
Take 4, and place it at every possible position in each of the previous numbers: 4321, 3421, 3241, 3214, 4231, 2431, 2341, 2314, ...
Continue indefinitely.
This takes approx. 10 seconds to calculate every permutation of a 9-digit number = 362880 permutations
Code:Public Class Robust_Permutator 'This list stores each number within the raw number Private Initial_Number_List As List(Of Integer) 'This list stores the first number within the raw number, in order to pass it into the permutation function Private Initial_Permutations_List As List(Of Integer) Private Sub btn_Permutate_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn_Permutate.Click 'Initialise the lists Initial_Number_List = New List(Of Integer) Initial_Permutations_List = New List(Of Integer) 'This loop loads all of the numbers within the raw number into the Number_List, starting from the second number For Number = 1 To txt_RawNumber.TextLength - 1 Initial_Number_List.Add(Int16.Parse(txt_RawNumber.Text.Substring(Number, 1))) Next 'Add the first number in the raw number to the Permutations_List to set it up Initial_Permutations_List.Add(Int16.Parse(txt_RawNumber.Text.Substring(0, 1))) 'Disable the button btn_Permutate.Enabled = False 'Make the progress bar visible prg_Permutations.Visible = True 'Initialise the background worker bgr_Permutator.RunWorkerAsync() End Sub Private Sub txt_RawNumber_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles txt_RawNumber.TextChanged 'Enable the button if the value in the textbox is a number of at least 2 digits btn_Permutate.Enabled = (IsNumeric(txt_RawNumber.Text) And txt_RawNumber.TextLength > 1) End Sub Private Function Permutate(ByVal Worker As System.ComponentModel.BackgroundWorker, ByVal Numbers As List(Of Integer), ByVal Permutated_Combinations As List(Of Integer)) As String 'Declare a background worker and assign it to the Worker parameter Dim bgrWorker As System.ComponentModel.BackgroundWorker = Worker 'Declare a list and assign it to the Numbers parameter Dim Number_List As List(Of Integer) = Numbers 'Declare a list and assign it to the Permutated_Combinations parameter Dim Permutations_List As List(Of Integer) = Permutated_Combinations 'Declare a variable to record the current number of objects in the Permutations_List Dim Permutation_Count As Integer = Permutations_List.Count 'Declare a variable to hold the currently selected Permutations_List number as a string Dim Current_Number As String 'Declare a variable that will be manipulated and added to the Permutations_List Dim Temporary_Number As String 'Loop through each of the original numbers in the Permutations_List For List_Index As Integer = 0 To Permutation_Count - 1 'Convert the current number to a string for manipulation Current_Number = Permutated_Combinations(List_Index).ToString() 'Loop through each position in the Current_Number For Place_Holder As Integer = 0 To Current_Number.Length 'Assign the Current_Number to the Temporary_Number Temporary_Number = Current_Number 'Insert the first number in the Number_List into the Temporary_Number string at the current position and add the new number to the Permutations_List Permutations_List.Add(Int64.Parse(Temporary_Number.Insert(Place_Holder, Number_List(0).ToString()))) Next Next 'Remove the first number in the Number_List Number_List.RemoveAt(0) 'Loop through the Permutations_List until the last original number For List_Index As Integer = 0 To Permutation_Count - 1 'Remove the first number in the list Permutations_List.RemoveAt(0) Next 'Update the UI thread with the number of recursions left to go bgrWorker.ReportProgress(0, Number_List.Count) 'Check whether there are any more numbers in the Numbers_List If Number_List.Count = 0 Then 'Declare and initialise a new stringbuilder Dim Permutated_Numbers As New System.Text.StringBuilder 'Loop through each number in the Permutations_List For List_Index As Integer = 0 To Permutations_List.Count - 1 'Add the string representation to the stringbuilder Permutated_Numbers.AppendLine(Permutations_List(List_Index).ToString()) Next 'Return all of the permutated values Return Permutated_Numbers.ToString() Else 'Call the function from itself Return Permutate(bgrWorker, Number_List, Permutations_List) End If End Function Private Sub bgr_Permutator_DoWork(ByVal sender As System.Object, ByVal e As System.ComponentModel.DoWorkEventArgs) Handles bgr_Permutator.DoWork 'Declare a background worker and assign it to sender Dim Worker As System.ComponentModel.BackgroundWorker = DirectCast(sender, System.ComponentModel.BackgroundWorker) 'The background worker returns the permutated values e.Result = Permutate(Worker, Initial_Number_List, Initial_Permutations_List) End Sub Private Sub bgr_Permutator_ProgressChanged(ByVal sender As System.Object, ByVal e As System.ComponentModel.ProgressChangedEventArgs) Handles bgr_Permutator.ProgressChanged 'Update the progress bar value prg_Permutations.Value = (CDbl(txt_RawNumber.TextLength) - CDbl(e.UserState)) / CDbl(txt_RawNumber.TextLength) * 100 End Sub Private Sub bgr_Permutator_RunWorkerCompleted(ByVal sender As System.Object, ByVal e As System.ComponentModel.RunWorkerCompletedEventArgs) Handles bgr_Permutator.RunWorkerCompleted 'Fill the permutations textbox with the permutated values txt_Permutations.Text = DirectCast(e.Result, String) 'Make the progress bar invisible prg_Permutations.Visible = False 'Enable the button btn_Permutate.Enabled = True End Sub End Class
Last edited by MaximilianMayrhofer; May 6th, 2008 at 12:51 PM.
- VS2008 Express, Access, SQL Server 2005 Express, VB/C#/ADO.NET -
Rate posts that have been helpful to you! It's a way of giving back to someone who has helped you
ASUS V1S-B1 Intel Core 2 Duo T7700 (2.40GHz) 15.4" Wide SXGA+ (1680x1050) 2GB DDR2 + 1GB Turbo Memory 160GB HDD DVD Super Multi Nvidia 8600GT 512MB Notebook w / Microsoft Windows Vista Business Edition![]()
SQL Server 2005 Express Connection Strings|SQL Tutorial 1|SQL Tutorial 2|Introduction to ADO.NET|Custom Calendar
Might be a quick and dirty one but so were ours, I like the novel idea of the background worker for this, and making it generic. Was thinking of that when I hardcoded 4 loops in and wouldn't have been nice altering that way. Nice different take there! you too Leeroy Jenkins ??!! :P nothing wrong with keeping it simple - if it is homework or Icyculyr is at a novice level at the mo, then yours is the one which'll be used!
Please rate this post if it was useful for you!
Please try to search before creating a new post,
Please format code using [ code ][ /code ], and
Post sample code, error details & problem details
Thanks for your replies...
>>It's not homework, nor am I a noviceI just didn't want to spend time figuring it out -.- (nor did I have any)
Cheers
Icyculyr
lol, I am simpleMakes it easier for me to understand until I am big and brainy like you guys
lol.
And you lazy monkey Icyculyr! lol. '_'
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
Haha, why be pro-active when I have a whole community of people to do things for me? LOLAnd you lazy monkey Icyculyr! lol. '_'
I'm just joking, but seriously I was busy, I didn't have time, I was thinking how to calculate how many different combinations there was..
it's not 4^4, is it 4*4? I don't know..
Cheers
Icyculyr
1 Digit there is 1 combination
2 digits there are A B and B A combinations SO 2.
3 digits A B C, A C B, B A C, B C A, C A B, C B A. So 6 combinations
4 digits theres 24 combinations.
So we are going 1, 2, 6, 24. Can you see a pattern? Want me to work out 5 digits and their combinations?
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
Its simple. THe penny just dropped.
4 numbers to pick from (the user has put 4 numbers into the program) A B C D for example.
There are 4 possible options for the first choice.
There are then 3 possible options for the second choice.
There are then 2 possible options for the third choice.
And that leaves 1 possible option for the last choice.
So 4 * 3 * 2 * 1 = 24. 24 possibilities.
So to work out 5 possibilities 5 * 4 * 3 * 2 * 1 = 120.
6 possibilities = 6 * 5 * 4 * 3 * 2 * 1 = 720.
So you can work out how many possibilities there are. I wouldn't recomend hard coding for 5 digits +. 4 is easy, 5 and above is rediculouse.
Lerroy
"η β π", or "Eta Beta Pi" (Eat A Better Pie)
01001000
01000101
01001100
01010000
My Own Code - WordCounter
Useful Forum Links -Reputation - What is it?
Thanks, that makes sense
Cheers
Icyculyr