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Thread: Proving De Morgan's Law

  1. #1

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    Proving De Morgan's Law

    Hi guys!

    I need to prove De Morgan's law for a logic class. My friend and I were successful with the first theorem:

    ~(P^Q)<=>~Pv~Q

    1. ~(PvQ) |P(1)
    2. P |A(2)
    3. PvQ |(vIntro) 2 (2)
    4. falsum |(~Elim) 1,3 (1,2)
    5. ~P |(~Intro) 2,4 (1,2)
    6. Q |A(6)
    7. PvQ |(vIntro) 6 (6)
    8. falsum |(~Elim) 1,7 (1,6)
    9. ~Q |(~Intro) 6,8 (1,6)
    10. ~P^~Q |(^Intro) 5,9 (1)

    I've been trying to solve the second theorem but I think that I'm stuck. Can you help me prove ~(pvq)<=>~p^~q?

    Thanks!!!

  2. #2
    Only Slightly Obsessive jemidiah's Avatar
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    Re: Proving De Morgan's Law

    Do you mean you want help proving the other direction (for some reason), that is ~Pv~Q => ~(P^Q)? Or do you want help proving the other theorem, ~(PvQ) <=> ~P^~Q? [that is, with "and" and "or" switched].

    If it's the first one I think you just proceed by cases with v elimination. If it's the second it should be at least similar to this one... but maybe it's not in some subtle way? I proved these last semester but my formal logic is draining out of me....
    The time you enjoy wasting is not wasted time.
    Bertrand Russell

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