I wrote this for my own usage, maybe someone here can benefit from it(sorry about the fact that there are no comments).
Tested in Firefox 0.9 and Internet Explorer 6.0Code:function hextorgb(n1,n2,n3,n4,n5,n6) { n1 = replacevals(n1); n2 = replacevals(n2); n3 = replacevals(n3); n4 = replacevals(n4); n5 = replacevals(n5); n6 = replacevals(n6); var returnval = ((16 * n1) + (1 * n2)); var returnval1 = 16 * n3 + n4; var returnval2 = 16 * n5 + n6; return ((16 * n1) + (1 * n2))+","+((16 * n3) + (1 * n4))+","+((16 * n5) + (1 * n6)); } function replacevals(n) { if (n == "a") { n = "10"; } if (n == "b") { n = "11"; } if (n == "c") { n = "12"; } if (n == "d") { n = "13"; } if (n == "e") { n = "14"; } if (n == "f") { n = "15"; } return n } function replacevalsreverse(thenum) { if (thenum == 10) { thenum = "a"; } if (thenum == 11) { thenum = "b"; } if (thenum == 12) { thenum = "c"; } if (thenum == 13) { thenum = "d"; } if (thenum == 14) { thenum = "e"; } if (thenum == 15) { thenum = "f"; } return thenum; } function rgbtohex(num1, num2, num3) { return calc10to16(num1) + calc10to16(num2) + calc10to16(num3); } function calc10to16(num) { if (num < 16) { var thenum = replacevalsreverse(num); return thenum; } else { var themod=num % 16; var thenum=((num-themod) / 16); thenum = replacevalsreverse(thenum) themod = replacevalsreverse(themod) return ""+thenum+themod } } alert(hextorgb("1","0","1","0","1","0")); alert(rgbtohex("40", "73", "212"));


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