C - 8 Queens Problem

Hi,

I saw a very cryptic code for 8 queens problem in the internet.

Place 8 queens in a chess board such that no other queen is in the same row, column and diagnol.

Code:

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# include<stdio.h>
int v,i,j,k,l,s,a[99];
main()
{
for(s=8;*a-s;v=a[j*=v]-a[i],k=i<s,j+=(v=j<s&&(!k&&!!printf(2+"\n\n%c"-(!l<<!j)," #Q"[l^v?(l^j)&1:2])&&++l||a[i]<s&&v&&v-i+j&&v+i-j))&&!(l%=s),v||(i==j?a[i+=k]=0:++a[i])>=s*k&&++a[--i]);
printf("\n\n");
}

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My Code

Code:

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# include<stdio.h>
# define Q  8
struct POINT {int x,y;};
POINT q[Q];
int N;
bool chkAll(int x){
        for ( int i =x ; i >=0 ; i--)
        for(int j = i - 1; j >= 0 ; j--)
        if(q[i].x == q[j].x || q[i].y == q[j].y ||
          q[i].x + q[i].y == q[j].x + q[j].y ||
          q[i].x - q[j].x == q[i].y - q[j].y)
        return false; return true;
}
void MoveQueen(int x){
       
        if(x >= Q)
        {       
                printf("\n\nSolution : %d \n\n\t",++N);
                for(int j=0;j<Q;printf("\n\t"),j++)
                for(int i=0;i<Q;((q[j].x==j) && (q[j].y==i))?printf("Q%c",179) : printf("_%c",179),i++);
                return;
        }       
       
        for (int j = 0; j < Q ;q[x].x = x,j++){        q[x].y = j;
                  if(chkAll(x)) MoveQueen(x + 1);
        }
}
void main(){for (int i = 0; i < Q; q[0].x = 0,q[0].y = i,MoveQueen(1),i++);}

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Regards,
Pradeep

Could you deobfuscate that stuff?

Hi,

The code which I found in the internet.. ??????... I have no clue what it does but when compiled runs like a charm...

The problem is place 8 queens on a chess board in such a way that no other queen falls in the same diagnoal and verticle and horizontal.

Check my games section in my website, I have made that game in VB, there is a cheat code also which will give you the list of solutuions...

Regards,
Pradeep

The program works great!! Just one thing, can you put comments on your code. i am trying to learn how to program and it would really help me out.