[VB6] Rotate Image

Hi Guys,

Do you have any idea to rotate image from VB6.0 (just the way windows photo viewer did).
I made an image viewer (zoom in, zoom out) to compare image, the problem is I can't rotate the image.
Kindly advice..

Thanks,
Jefri

Found on a german VB-Website: http://www.vbarchiv.net/tipps/details.php?id=938

Code:

---

Private Const pi = 3.14159265359

Public Sub RotatePicture(ByVal picSource As PictureBox, ByVal picDest As PictureBox, Optional ByVal Angle As Long = 0)
 
  ' cp0 - cp3 = Color of single Pixel
  Dim cp0 As Long, cp1 As Long
  Dim cp2 As Long, cp3 As Long
 
  ' Picture-Dimensions
  Dim w1 As Long, h1 As Long
  Dim w2 As Long, h2 As Long
 
  Dim p1x As Double, p1y As Double
  Dim p2x As Double, p2y As Double
  Dim n As Double, r As Double, a As Double
 
  picSource.AutoSize = True
  picSource.Visible = False
 
 
  picSource.AutoRedraw = True
  picDest.AutoRedraw = True
 
  picSource.ScaleMode = vbPixels
  picDest.ScaleMode = vbPixels
 
 
  Set picDest.Picture = Nothing
  picDest.Cls
 
  w1 = picSource.ScaleWidth \ 2
  h1 = picSource.ScaleHeight \ 2
  w2 = picDest.ScaleWidth \ 2
  h2 = picDest.ScaleHeight \ 2
 
  ' Angle = pi * (Angle / 180)
  If w2 < h2 Then n = h2 Else n = w2
  n = n - 1
 
  For p2x = 0 To n
    For p2y = 0 To n
      ' Calculate Position
      If p2x = 0 Then a = pi / 2 Else a = Atn(p2y / p2x)
      r = Sqr(p2x * p2x + p2y * p2y)
      p1x = r * Cos(a + (pi * Angle / 180))
      p1y = r * Sin(a + (pi * Angle / 180))
 
      cp0 = picSource.Point(w1 + p1x, h1 + p1y)
      cp1 = picSource.Point(w1 - p1x, h1 - p1y)
      cp2 = picSource.Point(w1 + p1y, h1 - p1x)
      cp3 = picSource.Point(w1 - p1y, h1 + p1x)

      If cp0 <> -1 Then picDest.PSet (w2 + p2x, h2 + p2y), cp0
      If cp1 <> -1 Then picDest.PSet (w2 - p2x, h2 - p2y), cp1
      If cp2 <> -1 Then picDest.PSet (w2 + p2y, h2 - p2x), cp2
      If cp3 <> -1 Then picDest.PSet (w2 - p2y, h2 + p2x), cp3
    Next p2y
  Next p2x
 
  Set picDest.Picture = picDest.Image
End Sub

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Not tested!