[RESOLVED] Calculate the Age

[dbasenoob]

How can i get my exact age? i make a code but it doesn't work. i want to happen is calculate the age. date now - date of birth then will show my age.


<?php
$day = $_POST['day']; //using select or drop down list
$month = $_POST['month']; //using select or drop down list
$year = $_POST['year']; //using select or drop down list
$age = date(("m-d-Y") - ($month.$day.$year));

echo "<h1>Your age now is $age </h1>";
?>

[kows]

first, use mktime() to create a Unix timestamp.

$birthdate = mktime(0, 0, 0, (int) $_POST['month'], (int) $_POST['day'], (int) $_POST['year']);

then, subtract the years. if you're only interested in the year:

echo "you are " . (date('Y') - date('Y', $birthdate)) . " years old.";

alternatively, if you are not storing the $birthdate variable in a database or something, you could make it even more simple:

echo " you are " . (date('Y') - (int) $_POST['year']) . " years old.";

[dbasenoob]

thanks it works... but how could i use the day and month? let say my birthday is august 25 1988 and my current age is 21. when august 25 past my age will be 22? how could i code it?

[kows]

the first solution in my post that makes use of mktime() will take the day and month of the year into account. the second method only deals with the year.