Simpile Geometry/Trig

[gwdash]

I have a right triangle in which i know sides a,b, and c:

1
/|
/ |
a / |
/ | c
/ |
/ |
2 /______ |3
b


I need to find 1, 2, and 3

3 is obviously 90, and if i can find one other, i can find the third, so i was thinking about using ArcCosin. But i am new at Trig, so i'm really not sure. (This needs to be done in VB)

[Sam Finch]

you don't have an arccosine in VB, but you do have an arctangent.

Tan(angle 2) = c/b

angle 2 = ATan(c/b)

[gwdash]

Great. It works perfectly