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Click to See Complete Forum and Search --> : Word, Passowrd, number, sybols generator


met0555
Apr 20th, 2009, 04:35 PM
Public Function PasswordGenerator(ByVal lngLength As Long) _
As String

On Error GoTo Err_Proc
Dim strResult As String

Dim iChr As Integer
Dim c As Long

Dim iAsc As String



For c = 1 To lngLength

' Randomly decide what set of ASCII chars we will use
iAsc = Int(3 * Rnd() + 1)

'Randomly pick a char from the random set
Select Case iAsc
Case 1
iChr = Int((Asc("Z") - Asc("A") + 1) * Rnd() + Asc("A"))
Case 2
iChr = Int((Asc("z") - Asc("a") + 1) * Rnd() + Asc("a"))
Case 3
iChr = Str((Asc(" ") - Asc("@") + 1) * Rnd() + Asc("@"))
Case 3
iChr = Asc((Asc("9") - Asc("0") + 1) * Rnd() + Asc("0"))
Case Else
Err.Raise(20000, , "PasswordGenerator has a problem.")
End Select

strResult = strResult & Chr(iChr)

Next c

PasswordGenerator = strResult

Exit_Proc:
Exit Function

Err_Proc:
MsgBox(Err.Number & ": " & Err.Description, _
vbOKOnly + vbCritical)
PasswordGenerator = vbNullString
Resume Exit_Proc

End Function

Hack
Apr 21st, 2009, 05:35 AM
Moved To VB6 CodeBank

met0555
Apr 21st, 2009, 06:48 AM
but it's works on VB.NET 3.5 and ASP.NET 3.5

mendhak
Apr 21st, 2009, 10:42 AM
You're using labels and GOTOs and Int() and Asc() and Err, though, none of which should be used in VB.NET.