kedaman
Feb 9th, 2001, 09:12 PM
You want to draw a sine curve that is angled?
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Click to See Complete Forum and Search --> : draw curved lines. kedaman Feb 9th, 2001, 09:12 PM You want to draw a sine curve that is angled? treklipper Feb 10th, 2001, 11:02 AM Yep! I would like to draw a curved line that is angled. It should work for angles from 1 to 360 kedaman Feb 10th, 2001, 11:44 AM Const deg2rad = 1.74527777777778E-02 offsetx = ScaleWidth \ 2 offsety = ScaleHeight \ 2 amplitude = ScaleWidth \ 8 frequency = 0.01 phi = 120 * deg2rad 'to convert degree to radians, multiply with pi/180 length = 1000 centerx = ScaleWidth \ 2 centery = ScaleHeight \ 2 For pixelx = 0 To length Y = offsety + Sin(pixelx * frequency) * amplitude X = offsetx + pixelx dx = -centerx + X dy = -centery + Y r = Sqr(dx * dx + dy * dy) theta = Sgn(dy) * ArkTangent(dy, dx) + phi PSet (centerx + Cos(theta) * r, centery + Sin(theta) * r) Next pixelx End Sub I did this one using guv's safe arctan that you can get here: http://forums.vb-world.net/showthread.php?s=&threadid=53924 treklipper Feb 10th, 2001, 04:21 PM Hi! There was some of your code I did not understand. This line of code: theta = Sgn(dy) * ArkTangent(dy, dx) + phi What sort of a function is ArkTangent? It is not anywhere in the code you posted parksie Feb 10th, 2001, 04:45 PM You get ArkTangent from the link he quoted :rolleyes: kedaman Feb 10th, 2001, 04:45 PM go for the link and copy guv's code for it ;) Sastraxi Feb 14th, 2001, 09:38 PM Or you could use sin and cos to do it.... but only if the curve was square (eg X1=50,X2=0,Y1=50,Y2=0) then the centerpoint (origin) would be 0,50 and so on...) vbforums.com
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