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Thread: Here's something to develop

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  1. #1

    Thread Starter
    pathfinder NotLKH's Avatar
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    Apr 2001
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    Here's something to develop

    Lets say you have a group of numbers, all distinct.

    They are represented by an equation, lets say G = C1+C2+C3...+Cn

    Such that G is a group of N integer elements such that there sum is mTargVal.
    The N elements are distinct, ie... each one of them is not equal to any other of them.

    Lets say that the smallest element in the group G = mCellLow,
    and the largest element is mCellHigh.

    For Example, lets say that N = 6
    and mCellLow = 0
    and mCellHigh = 18
    and mTargVal = 16

    1. Determine a fucntion that tightens the limits...mCellLow and mCellHigh
    2. Determine a function that returns what values MUST BE USED in this range.


    In the example that I gave to you, you will see that:

    If 5 of the numbers are 0 1 2 3 4, {The smallest set of N-1 numbers available} that the maximal mCellHigh really could be is 6.

    This is because if you add the N-1 lowest possible values together, you have created the most minimal sum that N-1 of those elements can add to.

    Which, if you then subtract from the targvl, you see that the most maximal value of a c could be only 6.

    So the real range that mCellLow and mCellHigh could be is 0 and 6.

    Using this as an example, and any others that you can think of, I am certain you can acheive #1.


    Now, Number 2 is a bit more complex, however, when all is said and done, it is a very simple function.

    Try by hand the following example:

    Using 5 distinct numbers, 3 <= Cn <= 18
    and those 5 numbers add to 27

    What numbers MUST be used?
    {BTW, this examples solution has tightened the C Limits}

    {I will provide more examples in the morning, but the answer to this is:

    You Are Required to use numbers in the range : 3 <= C <= 9
    3 Numbers Ascending {Inclusive} from 3 { 3 -> 5 }
    To Add To 27
    When you must use 5 Numbers GTE 3 and LTE 9
    Once and only once

    }

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