Click to See Complete Forum and Search --> : [RESOLVED] Pythagoras and I
BillGeek
Oct 15th, 2007, 03:46 AM
Hi All
Yet again, my basic mathematical skills (non-existent now) has failed me. :( I'm trying to apply the theory of pythagoras from a different perspective. Given the following, how would I be able to calculate x / y?
http://www.freewebs.com/billgeek/pythagoras.jpg
x = y
So this is where I get stuck:
r^2 = x^2 + y^2
... 1^2 = x^2 + y^2
... 1 = Sqrt(x^2 + y^2)
See the problem, or am I just having one of those days again? :rolleyes:
Any help would be appreciated! :)
zaza
Oct 15th, 2007, 05:13 AM
Fill in x = y....
But surely if x = y, then x/y = 1...?
BillGeek
Oct 15th, 2007, 06:09 AM
Nope. If you say x and/or y = 1 then:
r^2 = x^2 + y^2
Therefore: 1^2 = 1^2 + 1^2
Which means: 1 = 1 + 1... :confused:
03myersd
Oct 15th, 2007, 06:16 AM
Right lets start from scratch.
R = 1 and it is the hypotenuse
y = x
So R^2 = y^2 + x^2
Since y = x: R^2 = x^2 + x^2 = 2x^2
R^2/2 = x^2
Sqrt(R^2/2) = x
x = Sqrt(1^2/2)
x = Sqrt(0.5)
x = 0.71
Since x = 0.71 then y also = 0.71
Hope this is clear enough.
TheBigB
Oct 15th, 2007, 06:55 AM
table-wise
Step 1: Enter given values (hypotenuse = c)
x | x²
-----------
a |
b |
-----------
c 1 | 1
Step 2: Split the 1 and Squareroot it.
x | x²
-----------
a 0,71| 0,5
b 0,71| 0,5
-----------
c 1 | 1
BillGeek
Oct 15th, 2007, 07:25 AM
03myersd :thumb: Nice one! ;)
So in theory... whenever X = Y, you will have:
x = Sqrt(r^2/2)
EG:
Say X = 4 and X = Y
x = Sqrt(r^2/2)
Therefore: 4 = Sqrt(r^2/2)
Therefore: 16 = r^2/2
Therefore: 32 = r^2
Therefore: r = 5.656
Original Theory:
r^2 = 4^2 + 4^2
Therefore: r^2 = 16 + 16
Therefore: r^2 = 32
Therefore: r = 5.656
Interesting... :)
Thanks guys! A lot of help!!!
zaza
Oct 15th, 2007, 07:46 AM
Nope. If you say x and/or y = 1 then:
r^2 = x^2 + y^2
Therefore: 1^2 = 1^2 + 1^2
Which means: 1 = 1 + 1... :confused:
I think you'll find that "x/y" is terminology for "x divided by y" which is why, if x = y, x/y = 1.
But before 03myersd spoilt it, I was trying to prod you in the direction of realising that x = y and filling it in to your equation...
Incidentally, regarding your last point, when the X and Y legs are equal then the corner angle must satisfy tan A = 1 - i.e. A = 45o. Since this is the case, then all such triangles are similar, and the sides just scale.
03myersd
Oct 15th, 2007, 07:48 AM
Correct!
zaza
Oct 15th, 2007, 07:51 AM
...and BillGeek was originally asking how to calculate x/y....
BillGeek
Oct 15th, 2007, 11:08 PM
I think you'll find that "x/y" is terminology for "x divided by y" which is why, if x = y, x/y = 1.
Sorry, I did not realize it. I thought it was "x or y"...(Perhaps that's why I had horrible marks for maths :D)
Thanks for the help you guys!
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