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Yunie
Sep 7th, 2007, 05:29 AM
Given that x = 1 1/2 is the only solution to the equation 4x^2 - ax + b = 0, find the value of a and of b.
Please show and explain your workings, thanks a lot! :)
zaza
Sep 7th, 2007, 05:44 AM
What does a generic quadratic look like when factorised? What must be true if there is only one root? What do you get when you expand out of the brackets?
Yunie
Sep 7th, 2007, 06:02 AM
Haha...I don't know how to answer your above 3 questions cos I don't really understand...so that's why I could not solve or understand this problem...
But still, below is the working solution from my assignment book and I really wish you could explain it to me cos I don't really understand why the question is done in that particular way. Thanks.
Here is the working solution from my assignment book but I don't really understand...
Since x = 1 1/2 is the only solution, the eqn is a perfect square.
--> (2x - 3)^2 = 0
4x^2 - 12 + 9 = 0
By comparison, a = 12, b = 9
So, from the working solutions, does it mean that since x = 1 1/2, it has to be a perfect square? I don't understand...hmm...
opus
Sep 7th, 2007, 06:24 AM
For quadratic equations in the form of:
0= x^2 +px +q
The two possible solutions for x are (using the so called pq-formula):
x1= -p/2 + squareroot( (p/2)^2 -q)
x2= -p/2 - squareroot( (p/2)^2 -q)
In your case there shall be only one solution, in this case the squareroot-part has to be 0. But this can only be true if (p/2)^2=q.
I hope you can take from here!
krtxmrtz
Sep 7th, 2007, 07:12 AM
Haha...I don't know how to answer your above 3 questions cos I don't really understand......
I think zaza means you're not going to get too far if you don't understand the theory.
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