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Jun 26th, 2007, 02:06 PM
#1
Thread Starter
Lively Member
Finding latest file in a directory
Hello there I'm not to familer with working with directorys in PHP as I dont normally work with them in this in way. However what I'm after is a some php that will find the latest file uploaded into a directory and also its size and echo the name of the file and its size out. ie
Camera.jpg 26/06/07
Anyone have a simple script that can accomplish this?
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Jun 26th, 2007, 05:56 PM
#2
Re: Finding latest file in a directory
this may help you (From http://www.php.net):
PHP Code:
<?php
function permission($filename)
{
$perms = fileperms($filename);
if (($perms & 0xC000) == 0xC000) { $info = 's'; }
elseif (($perms & 0xA000) == 0xA000) { $info = 'l'; }
elseif (($perms & 0x8000) == 0x8000) { $info = '-'; }
elseif (($perms & 0x6000) == 0x6000) { $info = 'b'; }
elseif (($perms & 0x4000) == 0x4000) { $info = 'd'; }
elseif (($perms & 0x2000) == 0x2000) { $info = 'c'; }
elseif (($perms & 0x1000) == 0x1000) { $info = 'p'; }
else { $info = 'u'; }
// владелец
$info .= (($perms & 0x0100) ? 'r' : '-');
$info .= (($perms & 0x0080) ? 'w' : '-');
$info .= (($perms & 0x0040) ? (($perms & 0x0800) ? 's' : 'x' ) : (($perms & 0x0800) ? 'S' : '-'));
// группа
$info .= (($perms & 0x0020) ? 'r' : '-');
$info .= (($perms & 0x0010) ? 'w' : '-');
$info .= (($perms & 0x0008) ? (($perms & 0x0400) ? 's' : 'x' ) : (($perms & 0x0400) ? 'S' : '-'));
// все
$info .= (($perms & 0x0004) ? 'r' : '-');
$info .= (($perms & 0x0002) ? 'w' : '-');
$info .= (($perms & 0x0001) ? (($perms & 0x0200) ? 't' : 'x' ) : (($perms & 0x0200) ? 'T' : '-'));
return $info;
}
function dir_list($dir)
{
if ($dir[strlen($dir)-1] != '/') $dir .= '/';
if (!is_dir($dir)) return array();
$dir_handle = opendir($dir);
$dir_objects = array();
while ($object = readdir($dir_handle))
if (!in_array($object, array('.','..')))
{
$filename = $dir . $object;
$file_object = array(
'name' => $object,
'size' => filesize($filename),
'perm' => permission($filename),
'type' => filetype($filename),
'time' => date("d F Y H:i:s", filemtime($filename))
);
$dir_objects[] = $file_object;
}
return $dir_objects;
}
?>
// call:
<?php
print_r(dir_list('/path/to/you/dir/'));
?>
output sample:
Array
(
[0] => Array
(
[name] => api
[size] => 0
[perm] => drwxrwxrwx
[type] => dir
[time] => 28 May 2007 01:55:02
)
[1] => Array
(
[name] => classes
[size] => 0
[perm] => drwxrwxrwx
[type] => dir
[time] => 26 May 2007 00:56:44
)
[2] => Array
(
[name] => config.inc.php
[size] => 143
[perm] => -rw-rw-rw-
[type] => file
[time] => 26 May 2007 13:13:19
)
[3] => Array
(
[name] => index.php
[size] => 131
[perm] => -rw-rw-rw-
[type] => file
[time] => 26 May 2007 22:15:18
)
[4] => Array
(
[name] => modules
[size] => 0
[perm] => drwxrwxrwx
[type] => dir
[time] => 28 May 2007 00:47:40
)
[5] => Array
(
[name] => temp
[size] => 0
[perm] => drwxrwxrwx
[type] => dir
[time] => 28 May 2007 04:49:33
)
)
My usual boring signature: Something
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Jun 28th, 2007, 02:59 AM
#3
Re: Finding latest file in a directory
If you want to sort the array by time you need to use the creation time as indexes. You can do this by modifying just one function in the function dclamp posted:
Code:
$dir_objects[filectime($filename)] = $file_object;
You can now sort the contents of the array using ksort() for ascending and krsort() for descending. Obviously, the first / last element of the array depending in the function you use will be the latest file.
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