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Thread: [RESOLVED] solving simultaneous linear congruences

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  1. Dec 19th, 2006, 06:05 PM #1
    TBeck
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    Resolved [RESOLVED] solving simultaneous linear congruences

    I know how to do basic ones like this:
    x = 2 (mod 9)
    x = 3 (mod 7)

    but when there are coefficients infront of the xs I'm not sure how to go about solving it, for example something like:

    22x = 2 (mod 30)
    5x = 7 (mod 18)
    Last edited by TBeck; Dec 19th, 2006 at 07:42 PM. Reason: resolved
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