logic confusion, not sure how i got 12, but its not a choice .:Resolve:.

[voidflux]

Hello everyone i'm not sure how they got their answer here, it seems simple but I ended up getting 12 for $t3. Here is the question:
IF we are to run the below code on a pipleined 5 staged data path, how many cycles are needed? Assume there is no data forwarding hardware in the pipline.
After running, what is the data stored in $t3?
$t1 = 2
$t0 = 4 at the beginning.

add $t2, $t1, $t0 
xor $t3, $t2, $t1 
sub $t4, $t0, $t1 
j label 
add $t3,$t3,$t3 
... 
label: or $t3, $t1, $t0

A. $t3 = 8 , 11 cycles
B. $t3 = 4 , 10 cycles
C. $t3 = 6 , 10 cycles
D. $t3 = 6 , 11 cycles

I got 10 cycles and the naswer to be $t3 = 12.

Here is my reasoning.

first line:
add $t2, $t1, $t0 #$t2 = 6
xor $t3, $t2, $t1 # $t3 = 6 xor 2 would be 0110 xor 0010 = 0100 = 4
sub $t4, $t0, $t1 # $t4 = 2
j label #jump to label
add $t3,$t3,$t3
....
label: or $t3, $t1, $t0 # t3 = 2 or 4 = 0010 or 0100 = 0110 = 6

but now you must add $t3 = $t3 + $t3 = 6 + 6 = 12

I don't see where i'm misunderstanding...


Thanks!