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  1. #1

    Thread Starter
    New Member
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    Post ...

    ....
    Last edited by JJ6000; Oct 28th, 2006 at 10:32 AM.

  2. #2
    Frenzied Member
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    Re: Break- Even Points Question

    R=(500-2x)x
    R=500x-2(x^2)

    C=3600+100x+2(x^2)

    P=R-C

    P=500x-2(x^2)-3600-100x-2(x^2)

    P=-4(x^2)+400x-3600
    P/4=-x^2+100x-900

    Now solve :
    P=0
    0/4=-x^2+100x-900
    0=-x^2+100x-900

  3. #3
    Addicted Member Rassis's Avatar
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    Re: Break- Even Points Question

    Hi,

    There are two breakeven points. They are: Making C = R, the following equation is obtained: x^2 - 100.x + 900 = 0. Solving for x, one gets x = 10 units and x = 90 units.

    The number of sold units for which the revenue becomes a maximum is obtained making: dR/dx = 500 - 4.x = 0. Solving for x, one gets x = 125 units. At this point the manufacturer is making a loss, because the gross margin (GM = R - C = -3600 + 400.x - 4.x^2) is negative and equal to GM = -16,100 €.

    The number of sold units for which the gross margin becomes a maximum is obtained making: dGM/dx = 400 - 8.x = 0. Solving for x, one gets x = 50 units.

    See the attached Excel file for a better understanding.
    Attached Files Attached Files
    ...este projecto dos Deuses que os homens teimam em arruinar...

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