Right angle triangle problem

[ellclel]

Got a problem!
I have a right angle triangle and I know that one of the sides of the right angle is 80mm, i also know the hypotenuse would be half the size of the other sideof the right angle how would i work this out?

[NotLKH]

Got a problem!
I have a right angle triangle and I know that one of the sides of the right angle is 80mm, i also know the hypotenuse would be half the size of the other sideof the right angle how would i work this out?

So:
2 legs and an hypotenuse.

Leg1²+leg2²=Hypotenuse²

Say Leg1 = 80

Then, it seems you are saying Leg2 = 2*Hypotenuse, or Hypotenuse is = 1/2 that of Leg2.

But this clearly is incorrect, since in any right triangle, the Hypotenuse is always greater than either of the legs, per the properties of the Pythagorian equation.

So...

If you meant Hypotenuse = 2*Leg2, then the equation becomes:

80²+Leg2²=(2*Leg2)²

-Hope this helps
-Lou

[VBAhack]

Got a problem!
I have a right angle triangle and I know that one of the sides of the right angle is 80mm, i also know the hypotenuse would be half the size of the other sideof the right angle how would i work this out?

Welcome to the forums. If h is the hypotenuse and a and b are the legs, I think you mean the following:

a = 80
b = ?
h = 2b

How to find h and b?

Since h² = a² + b²

You can just substitute and solve.

[ellclel]

Thankyou for your help and sorry if the problem was to easy

[VBAhack]

I just read the thread again. The hypotenuse can't be smaller than either leg. I think NotLKH pointed this out. I believe something is wrong with the problem statement.

[jeroen79]

i also know the hypotenuse would be half the size of the other sideof the right angle

Indeed, this can't be true.

If it is the other way around then the triangle's angles will be 90, 60 and 30 degrees.