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Jun 21st, 2006, 05:39 PM
#1
Thread Starter
New Member
i need help badly and quick
Can anyone sort this one out for me pleassseeeee......................................................................................Th e istantaneous current and voltage in an electric circuit are given by
i = I cos 50pi t
v = Vcos (50 pi t + pi/6)
determine an expression for the instantaneous power in the circuit, p = iv, as the sum of two cosines.
If I is 3mA and V is 5 V, calculate the maximum value of p, giving your answer in watts correct to three sig figures, and the first positive value of t at which it occurs.
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Jun 22nd, 2006, 02:21 PM
#2
Addicted Member
Re: i need help badly and quick
I think you can follow, in part, the same steps that I described in the answer I gave to your previous post... The only difference is that, this time, you have a multiplication of variables instead of a summation. You can also use the GOAL-SEEK option but it is to be applied to the first derivate of p =i.v. This time, the result dp/dt must equal 0. Try to do it yourself.
Rui
...este projecto dos Deuses que os homens teimam em arruinar...
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