Click to See Complete Forum and Search --> : Geometry Puzzle
Thomas154321
Apr 29th, 2006, 12:42 PM
Draw a right-angled triangle.
3 ropes are attached to the midpoints of each side, and each rope is half the length of the side it is attached to. A goat is tied to the end of the rope on the hypotenuse, and two sheep are attached to the ropes on the shorter sides. The area of the triangle is 1 acre. Find the area that the goat can reach that the sheep cannot.
~
I'm not sure how hard this should be - it was written by a university professor for my Uncle who has limited mathematical knowledge but enjoys puzzles. I can't think where to start with it though. Thanks for any help. :)
Rassis
Apr 30th, 2006, 04:16 AM
If I understood it correctly, it seems that the sheep can reach everywhere inside the triangle or does its exterior count as well?
Thomas154321
Apr 30th, 2006, 06:51 AM
I've drawn a diagram of it. We want the red area. The blue circles represent the outside of where the sheep can reach.
Rassis
Apr 30th, 2006, 06:03 PM
First consider a generic circle with radius R and a rope connecting any two points. The area A limited by the rope and the circle is given by:
A = R^2*[a/2 sin(a/2)*cos(a/2)]
Where a is the angle formed by the two lines that connect the center of the circle and each of the two extreme points of the rope. Let us call it the inner-angle (perhaps the expression is not the most correct in English
).
Second, consider a right-angled triangle with sides X and Y and hypotenuse Z.
http://img67.imageshack.us/img67/5428/triangle1zj.jpg
The inner-angle a1 of the circle with diameter Y is given by:
a1 = (Pi) 2*arc.tan(X/Y)
And the inner-angle a2 of the circle with diameter X is given by:
a2 = (Pi) 2*arc.tan(Y/X)
If the area of the triangle is S, then S = ½*(X*Y)
Now, suppose X = 1. Because it is assumed that the area of the triangle S = 1, you have: Y = 2*1/1 = 2. And you get sequentially:
a1 = 2.2142974
a2 = 0.9272952
Ax = 0.0159119
Ay = 0.7071487
And finally the area A we are after is:
A = Az Ax Ay = (Pi)/8*(X^2 + Y^2) Ax Ay = 1.9634954 0.0159119 0.7071487 = 1.2404348
If X = Y = 1.4142136, you get A = 1.2853982 which is a maximum.
Rui
Thomas154321
May 1st, 2006, 04:57 AM
Super! I'll send it to my uncle and see if that's what the answer was supposed to be. That all makes sense though. Thanks. :thumb: :)
Rassis
May 1st, 2006, 01:24 PM
It was a pleasure.
Rui
vbforums.com
Copyright Internet.com Inc., All Rights Reserved.