Opening a File from a FIleListBox, PLEASE RESPOND

[Wonderer]

I have made a program with one form containing a DriveListBox, a DirListBox, and a FileListBox. What I want to know is how to make it so when a double click on a file in the file list box it opens that file.
I'd appreciate any help on this matter, thank you.

[dead]

Here, try this... this is assuming you are using notepad.

  Shell ("C:\Windows\notepad.exe ") & (File1.FileName)

Don't forget this is just a sample and may vary on the program. And you must obviously change the current Drive & Dir for it to even SEE the file.

[MidgetsBro]

if you are using a text box in your own program use this:

Dim FileName As String

Private Sub Command1_Click()

FileName = dir1.path & "\" & file1.filename
    F = FreeFile
    Open FileName For Input As #F
    Text1.Text = Input$(LOF(F), F)
    Close #F
End Sub

Private Sub file1_dblClick()

     call Command1_Click

End Sub

Public Declare Function ShellExecute _
 Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As _
Long, ByVal lpOperation As String, ByVal lpFile As String, _
ByVal lpParameters As String, ByVal lpDirectory As String, _
ByVal nShowCmd As Long) As Long

Public Const SW_SHOWNORMAL = 1


Private Sub Dir1_Change()
    File1.Path = Dir1.Path
End Sub

Private Sub File1_DblClick()

    If Len(Dir1.Path) <= 3 Then d = Dir1.Path & File1.filename
    If Len(Dir1.Path) > 3 Then d = Dir1.Path & "\" & File1.filename
    ShellExecute Me.hwnd, vbNullString, d, vbNullString, "c:\", SW_SHOWNORMAL

End Sub

Assuming that you have files other than Text files, use the following code to open them.

Private Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long) As Long

Private Sub File1_DblClick()
    ShellExecute hwnd, "open", File1, "", "", 1
End Sub