in the form of y = m x + c.

[lakitu]

Hi All!

I am trying to figure out how to solve problems like the one below. Any guidence would be appreciated.


Work out the equation of the straight line through (3, -7) and (6, -16) in the form y = m x + c.

m = (-7) - (-16) = 9 = -3
__________ ___
(3) - (6) -3

m = -3

y = mx + c

-7 = (-3)(3) + c
-7 = -9 + c
c = -9 - (-7)
c = -2

y = (-3)x + -2

That is what I have done so far, am I doing it correctly ?

[just_a_me]

Very close except c should be 2.

-7 = (-3)(3) + c
c = -7 - (-9)
c = 2

[lakitu]

ah silly mistake! thank you for your input. So the answer is correct then ? Its for homework you see.

Thanking you

[midhat]

i remember the two point form of line equation. if a line passes thru (x1,y1),(x2,y2) the eq will be

(y-y1)/(y2-y1)=(x-x1)/(x2-x1)


hen u can convert it to y=mx+c form