[RESOLVED] Silly problem..

[|2eM!x]

Say i wanted to code my script shorter, like so:

<?php
$handle = fopen('mytxt.txt', 'r');
$contents = (@fread($handle,filesize('mytxt.txt')))++;
fclose($handle);
$handle = fopen('mytxt.txt','w');
fwrite($handle,$contents);
fclose($handle);
echo $contents;
?>

instead of doing $contents++

why does that return a parse error? its the same exact thing i think

[k1ll3rdr4g0n]

A. Why would you have a add a one to the variable?
B. You don't loop when your reading a file, as PHP reads the whole file at once.

[visualAd]

The reason it doesn't work i becuase you are trying to incement a constant. It like saying:

1++

Which won't work becuase the value of one is a constant. The ++ operator increments the value by one and assigns it to that variable.

You can however use this, with the same effect:

$contents++ = (@fread($handle,filesize('mytxt.txt')));

Because you have put ++ at the end of $contents, it will not increment the value until the right part of the expression has been evaluated and asigned to $contents.

[|2eM!x]

That still doesnt work, gives me parse errors also :confused:
<?php
$filename = 'Users.txt';
$handle = fopen($filename,'r+');
$contents++ = (@fread($handle,filesize($filename)));
fwrite($handle,$contents);
echo $contents;
fclose($handle);
?>
php always baffles me at its wonderfully bad way of describing errors

[visualAd]

You'll have to do it as two lines. Sorry :blush:

$contents = (@fread($handle,filesize($filename)));
++$contents;

[|2eM!x]

Thanks visualad