[RESOLVED] Open Dynamic Child Form

[Tjoppie]

Hi all,

I've got a range of child forms which I want to open with a treeview.

Now I get the name of the form I need to open from the following code:

Private Sub JMSTreeView_AfterSelect(ByVal sender As System.Object, ByVal e As System.Windows.Forms.TreeViewEventArgs) Handles JMSTreeView.AfterSelect
 
        Me.lblTreeTitle.Text = "MAIN MENU | " & JMSTreeView.SelectedNode.FullPath
 
        '==========================================================================================
        Dim FileToOpen As String
        For intLoopIndex As Integer = 0 To (TreeData.Tables("Qry_Admin_TreeMenu_VBNET").Rows.Count) - 1
            If TreeData.Tables("Qry_Admin_TreeMenu_VBNET").Rows(intLoopIndex).Item(0) = e.Node.Tag Then
                FileToOpen = (TreeData.Tables("Qry_Admin_TreeMenu_VBNET").Rows(intLoopIndex).Item(6).ToString)
            End If
        Next intLoopIndex
 
        '=====================================================================================

Now my mind is saying to me that this should work. To open the form, I used the following code:

Dim MdiFrm As FrmMAIN
        Me.GlobalForm = Me
        Dim FrmNewChild As New FileToOpen
        FrmNewChild.MdiParent = MdiFrm
        'Me.Hide()
        FrmNewChild.Show()
 
    End Sub

Now I am getting at line: Dim FrmNewChild As New FileToOpen
The error: Type 'FileToOpen' is not defined

How do I get the right form to be opened, or how do I get the code to accept "FileToOpen" as the form to be opened?

Thanks

Rudi