spyder
Oct 12th, 2000, 01:44 PM
Greetings,
I have a Problem that is really nagging me. I have a VB app that is trying to get data in an Access 2000 .mdb
here is a code snippet
adoDriver = "Driver={Microsoft Access Driver (*.mdb)};"
adoPath = "dbq=" & DataBaseLocation & ";"
adouser = ";"
adoPassword = ""
Dim rs As ADODB.Recordset
' used temporarily until code is working
strConnection = adoDriver & adoPath & adouser & adoPassword
On Error GoTo handleErr
dbCheckOut.ConnectionString = strConnection
dbCheckOut.Open
cmCheckOut.ActiveConnection = dbCheckOut
cmCheckOut.CommandText = "select * from Machine"
rs = cmCheckOut.Execute
On Error GoTo 0
dbCheckout is the connection object
and cmCheckout is the command object
Both are declared public
The Problem is that the rs = mcCheckout.execute is saying invalid use of property and I have not clue as to why. I have looked in Technet and even downloaded a sample app from MS. And the sample code was "identical". And the references were nearly identical. Anyone have a clue as to why?
Thanks much
-=D=-
I have a Problem that is really nagging me. I have a VB app that is trying to get data in an Access 2000 .mdb
here is a code snippet
adoDriver = "Driver={Microsoft Access Driver (*.mdb)};"
adoPath = "dbq=" & DataBaseLocation & ";"
adouser = ";"
adoPassword = ""
Dim rs As ADODB.Recordset
' used temporarily until code is working
strConnection = adoDriver & adoPath & adouser & adoPassword
On Error GoTo handleErr
dbCheckOut.ConnectionString = strConnection
dbCheckOut.Open
cmCheckOut.ActiveConnection = dbCheckOut
cmCheckOut.CommandText = "select * from Machine"
rs = cmCheckOut.Execute
On Error GoTo 0
dbCheckout is the connection object
and cmCheckout is the command object
Both are declared public
The Problem is that the rs = mcCheckout.execute is saying invalid use of property and I have not clue as to why. I have looked in Technet and even downloaded a sample app from MS. And the sample code was "identical". And the references were nearly identical. Anyone have a clue as to why?
Thanks much
-=D=-