Math problem

[fallnwrld]

I know how to do this math problem by hand, but i wouldnt know how to get a program to do it..... This is the problem

INPUT is 11:
_____
2| 11 = 5 Remainder 1

Take the answer 5
(Divide it by 2)
_____
2| 5 = 2 Remainder 1

Take the answer 2
(Divide it by 2)
______
2 | 2 = 1 Remainder 0

Take the answer 1
(Divide it by 2)
______
2 | 1 = 0

Now you take the remainders backwards...the answer is
1011

How the hell can i do that?

[mutley]

send the code

[fallnwrld]

If i try to divide using code i will get a decimal for example 2/11 is 5.5... how can i get .5 to remainder 1

[LiNX]

Number = Text1.Text

Do
    Remain = Number Mod 2
    inText = Remain & inText
    Text2.Text = Text2.Text & Number & " | " & 2 & "_ Remain " & Remain & vbNewLine
    Number = Int(Number / 2)

Loop Until Remain = 0

Text2.Text = Text2.Text & inText

This should work... I've tested it, and it does with me


LiNX

[Edited by LiNX on 10-11-2000 at 08:45 AM]

[ceilidhallnight]

I'm not sure exactly how to write code for this problem, but I do know that Mod will give you the remainder of a division

example:

Dim math As Integer

math = 5 Mod 3
MsgBox math
you get the remainder 2

Hope this helps!

[jbart]

Disclaimer: I know this is not the best way to do this, but I was just throwing something together while working on another project. But it will return the answer you are looking for using the MOD operator.

Also, using \ for division returns just the integer portion.

Private Sub command1_click()
    Dim remainder1 As Integer
    Dim remainder2 As Integer
    Dim remainder3 As Integer
    Dim remainder4 As Integer
    Dim startNumber As Integer
    Dim divNumber1 As Integer
    Dim divNumber2 As Integer
    Dim divNumber3 As Integer
    Dim divNumber4 As Integer
    Dim result As String
    startNumber = 11
    
    divNumber1 = startNumber \ 2
    remainder1 = startNumber Mod divNumber1
    
    divNumber2 = divNumber1 \ 2
    remainder2 = divNumber1 Mod divNumber2
    
    divNumber3 = divNumber2 \ 2
    remainder3 = divNumber2 Mod divNumber3
    
    divNumber4 = divNumber3 \ 2
    If divNumber4 > 0 Then
        remainder4 = divNumber3 Mod divNumber4
    Else
        remainder4 = 1
    End If
    
    result = remainder4 & remainder3 & remainder2 & remainder1
    MsgBox result

Okay try this.
Put a textbox and command button on a form. Make sure the textbox and command button are off to the right of the form because the results will be printed on the form. In the command1 click event place this code:

IntegerToBinary (CInt(Text1.Text))

Add a module and paste this code

Sub IntegerToBinary(intNumber As Integer)
    Dim intResult As Integer
    Dim intRemainder As Integer
    
    intResult = Fix(intNumber / 2)
    intRemainder = (intNumber Mod 2)
    Form1.Print intResult & "     " & intRemainder
    
    If intResult = 0 Then
        Exit Sub
    Else
        IntegerToBinary (intResult)
    End If
    
End Sub

Then just read the right column from the bottom up. There is probably a better way to output the results but I'm too sick right now.

I'm fairly new still so I hope this helps.

[seaweed]

Try this one on for size...guaranteed to work every time! (at least with the number 11)

Paste the following into a forms code window (or change Form_Load to Main and put it in a basic module):

Option Explicit

Private Sub Form_Load()
    Dim Number As Long
    Dim Remainder As Long
    Dim Result As Long
    Dim Answer As String
    
    Number = CLng(InputBox("Enter a number, please:", "FallnWrld"))
    
    Do
        Remainder = GetRemainder(Number, Result)
        Number = Result
        Answer = CStr(Remainder) & Answer
    Loop While Result > 0
    
    MsgBox "Answer = " & Answer
    
    Unload Me
End Sub

Private Function GetRemainder(Number As Long, Result As Long) As Long
    Result = CLng(Int(Number / 2))
    GetRemainder = CLng(Int(Number Mod 2))
End Function

Who's the man???



Hope that helps!

[VBonliner]

'Need:
'Text1 for numerator
'Text2 for denominator
'Command1 for code below


Dim strRemaindor As String
Dim conRemaindor As String
Dim intNumerator As Integer
Dim intDenominator As Integer
Dim intRemaindor As Integer
Dim intResult As Integer
strRemaindor = ""
intNumerator = Text1
intDenominator = Text2
10
intResult = intNumerator \ intDenominator
intRemaindor = intNumerator Mod intDenominator
intNumerator = intResult
Select Case intRemaindor
Case 0
conRemaindor = "0"
Case 1
conRemaindor = "1"
Case 2
conRemaindor = "2"
Case 3
conRemaindor = "3"
Case 4
conRemaindor = "4"
Case 5
conRemaindor = "5"
Case 6
conRemaindor = "6"
Case 7
conRemaindor = "7"
Case 8
conRemaindor = "8"
Case 9
conRemaindor = "9"
End Select
strRemaindor = strRemaindor & conRemaindor
If intResult <> "0" Then GoTo 10
response = MsgBox("Rev Rem is: " & strRemaindor, vbOkOnly)