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Thread: [RESOLVED]Find the equation of the axis of symmetry and the vertex of x

  1. Dec 8th, 2004, 07:15 PM #1
    Arc
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    [RESOLVED]Find the equation of the axis of symmetry and the vertex of x

    Hey guys. This has to do with Porabala's and finding the Vertex and axis of symmetry. I know the basic function of how to do it, but I am not coming up with the correct answer.

    Here is the equation x = -3y2 + y + 4

    Now, I have found the y coordinate which is -1/6. Now I need to find the Vertex which is (? , -1/6).

    Basically all that has to be done is replace the y's in the equation with -1/6, but for some reason I am having trouble getting the correct answer.

    Any help is appreciated!
    Last edited by Arc; Dec 8th, 2004 at 09:39 PM.
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  2. Dec 8th, 2004, 09:39 PM #2
    Arc
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    Re: Find the equation of the axis of symmetry and the vertex of x

    Never mind I figured it out.
    y = 1/6; vertex = ( 49/12 , 1/6)

    I was using -1/6 instead of 1/6, which was totaly screwing everything up.
    -We have enough youth. How about a fountain of "Smart"?
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