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Sep 13th, 2004, 03:36 PM
#1
Thread Starter
Lively Member
Point me in the right direction.
Alright, i got assigned this, and have no idea how to begin. I'm not looking for an answer (wait, yes I am, but don't expect one). Could someone maybe give me a little guidence?
Let Yn be the sum of n independent rolls of a fair die. Find the probability that Yn is a multiple of 13, as n goes to infinity.
This is what I have, nothing more than a mathematical writing of the problem
lim P{Yn is a multiple of 13}
n-> inf.
Help me?
-mh
"Have you ever woken up, looked at yourself in the mirror, and said 'screw the diet, how fat can i possibly get'?"
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Sep 14th, 2004, 09:29 PM
#2
Fanatic Member
I'm just taking a wild guess here, but would the sum become inf and inf is just a symbol and not a number, so would there even be an answer?
"Can't" and "shouldn't" are two totally separate things.
All questions should be answered. All answers should be true. That is why I post.
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Sep 14th, 2004, 10:22 PM
#3
Fanatic Member
There is a different between the limit of x as it approaches infinity and infinity. The value may converge. I would suggest a table of values for the really low roll amounts (3+, as 2 and 1 can't reach 13)
Write a small computer program to do it for you. It would take hours to figure it out for 20 dice.
Don't pay attention to this signature, it's contradictory.
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Sep 14th, 2004, 10:32 PM
#4
Fanatic Member
I bet that the probability will close in on 1/13
Basicly, as amount of rolls becomes larger, ... uh, ok it was just a guess.
Don't pay attention to this signature, it's contradictory.
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Sep 14th, 2004, 10:32 PM
#5
Fanatic Member
Idea: solve this for multiples of 2, then 3, and 4. Maybe this will help?
Don't pay attention to this signature, it's contradictory.
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