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Click to See Complete Forum and Search --> : Split Function In Vb5


abhijit
Jan 23rd, 2004, 05:23 AM
Hi Folks,

Split function is not available natively in VB5. MSDN has provided a replacement for VB5.
Here is the code.

Public Function Split(ByVal sIn As String, Optional sDelim As _
String, Optional nLimit As Long = -1, Optional bCompare As _
VbCompareMethod = vbBinaryCompare) As Variant
Dim sRead As String, sOut() As String, nC As Integer
If sDelim = "" Then
Split = sIn
End If
sRead = ReadUntil(sIn, sDelim, bCompare)
Do
ReDim Preserve sOut(nC)
sOut(nC) = sRead
nC = nC + 1
If nLimit <> -1 And nC >= nLimit Then Exit Do
sRead = ReadUntil(sIn, sDelim)
Loop While sRead <> ""
ReDim Preserve sOut(nC)
sOut(nC) = sIn
Split = sOut
End Function

Public Function ReadUntil(ByRef sIn As String, _
sDelim As String, Optional bCompare As VbCompareMethod _
= vbBinaryCompare) As String
Dim nPos As String
nPos = InStr(1, sIn, sDelim, bCompare)
If nPos > 0 Then
ReadUntil = Left(sIn, nPos - 1)
sIn = Mid(sIn, nPos + Len(sDelim))
End If
End Function


This code doesn't work as smoothly as the split function in vb6.
Notice this array "Open ~ Close ~~ Send". This is not getting correctly split in this function.S
So I have made a slight change to the function.

Here is my changed function. Please review and comments.



Public Function Split(ByVal sIn As String, Optional sDelim As _
String, Optional nLimit As Long = -1, Optional bCompare As _
VbCompareMethod = vbBinaryCompare) As Variant
Dim sRead As String, sOut() As String, nC As Integer
If sDelim = "" Then
Split = sIn
End If
sRead = ReadUntil(sIn, sDelim, bCompare)
Do
ReDim Preserve sOut(nC)
sOut(nC) = sRead
nC = nC + 1
If nLimit <> -1 And nC >= nLimit Then Exit Do
sRead = ReadUntil(sIn, sDelim)
Loop While Len(sIn) <> 0 ''My Change Over here
ReDim Preserve sOut(nC)
sOut(nC) = sIn
Split = sOut
End Function


Cheers,
Abhijit