Hey all, it been a while since my last php project, and I guess I frogot everything........![]()
I am trying to get a result from db in mySql. But i always get this error Message:
Warning: Supplied argument is not a valid MySQL result resource in ...
Heres the relevant code:
ThanksPHP Code:$queryTeams = "SELECT * FROM teams WHERE Group = 'A'";
$resultTeams = mysql_query($queryTeams);
while($Team = mysql_fetch_array($resultTeams)) // this is where the error is pointing
Stephan





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