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Thread: can anyone confirm this

  1. Dec 9th, 2003, 01:47 AM #1
    dimava
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    can anyone confirm this

    http://www.cpcc.edu/academic_learnin...Asymptotes.htm

    is this a true easy way to find horizontal asymptotes?
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  2. Dec 9th, 2003, 11:51 AM #2
    TheManWhoCan
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    Yeah there's nothing wrong with that...
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  3. Dec 9th, 2003, 03:16 PM #3
    kedaman
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    vertical though, for horizontal it would be lim x->+ and -infinity
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    reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
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  4. Dec 10th, 2003, 12:31 AM #4
    dimava
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    kedman, if you scroll down it has 3 rules for horizontal
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  6. Dec 10th, 2003, 03:03 AM #5
    kedaman
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    convenient web design..
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    writing software in C++ is like driving rivets into steel beam with a toothpick.
    writing haskell makes your life easier:
    reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
    To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
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  7. Dec 11th, 2003, 12:54 AM #6
    jemidiah
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    The limit answer kedaman posted was more calculus based (and universal). The 3 rules on the bottom of that page are really pretty much just some algebraic representations of the calc. limit answer for polynomials. In fact, the part where they take the ratio of the highest two powers arises from the others not mattering as x approaches positive and negative infinity, something limits tell you.
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