can anyone confirm this

[dimava]

http://www.cpcc.edu/academic_learning/mathhandouts/Asymptotes.htm

is this a true easy way to find horizontal asymptotes?

[TheManWhoCan]

Yeah there's nothing wrong with that...

[kedaman]

vertical though, for horizontal it would be lim x->+ and -infinity

[dimava]

kedman, if you scroll down it has 3 rules for horizontal

[kedaman]

convenient web design..

[jemidiah]

The limit answer kedaman posted was more calculus based (and universal). The 3 rules on the bottom of that page are really pretty much just some algebraic representations of the calc. limit answer for polynomials. In fact, the part where they take the ratio of the highest two powers arises from the others not mattering as x approaches positive and negative infinity, something limits tell you.