After using the rule of the difference of cubes, how many x's can yo.:Resolved:.
Hello everyone, I had a question, I need to solve for all the x values, to find the x-intercepts.
If i had an equation like the following:
(x^4-x) = 0;
so i factor out an x
x(x^3 - 1) = 0;
now i have to use the differences of cubes formula:
x^3-a^3 = (x-a)(x^2+ax+a^2);
so u would have
x(x-1)(x^2 + x + 1);
so u have
x = 0, x = 1, but what do u do about the x^2+x+1?
I tried the quadratic equation and i get a - in the square root so what does this mean?
Thanks for listening,
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