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Jul 8th, 2003, 06:58 AM
#1
Rollover links...
I have had some help to make a simple rollover function in Javascript. And some code in HTML to execute it. It works great....when I have one picture...but if I add two pictures calling the same funtion, no one of the pictures will change if the mouse is over it. Any suggestions?
Here is a sample of the code...
Code:
<script language="Javascript">
function rollover (newpic) //Function
{
document.picture.src = newpic; //Sets pictures src = newpic
}
</script>
Code:
<img src="images/starlogo.gif" name="picture" border="0" onMouseOver="rollover('Rally/rally.gif');"
onMouseOut="rollover('images/starlogo.gif')">
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Jul 8th, 2003, 01:36 PM
#2
Into a .js file (or script tag):
Code:
function MM_swapImgRestore() { //v3.0
var i,x,a=document.MM_sr; for(i=0;a&&i<a.length&&(x=a[i])&&x.oSrc;i++) x.src=x.oSrc;
}
function MM_preloadImages() { //v3.0
var d=document; if(d.images){ if(!d.MM_p) d.MM_p=new Array();
var i,j=d.MM_p.length,a=MM_preloadImages.arguments; for(i=0; i<a.length; i++)
if (a[i].indexOf("#")!=0){ d.MM_p[j]=new Image; d.MM_p[j++].src=a[i];}}
}
function MM_findObj(n, d) { //v4.0
var p,i,x; if(!d) d=document; if((p=n.indexOf("?"))>0&&parent.frames.length) {
d=parent.frames[n.substring(p+1)].document; n=n.substring(0,p);}
if(!(x=d[n])&&d.all) x=d.all[n]; for (i=0;!x&&i<d.forms.length;i++) x=d.forms[i][n];
for(i=0;!x&&d.layers&&i<d.layers.length;i++) x=MM_findObj(n,d.layers[i].document);
if(!x && document.getElementById) x=document.getElementById(n); return x;
}
function MM_swapImage() { //v3.0
var i,j=0,x,a=MM_swapImage.arguments; document.MM_sr=new Array; for(i=0;i<(a.length-2);i+=3)
if ((x=MM_findObj(a[i]))!=null){document.MM_sr[j++]=x; if(!x.oSrc) x.oSrc=x.src; x.src=a[i+2];}
}
And in your html:
Code:
<img src="images/starlogo.gif" name="imageName" border="0" onMouseOver="MM_swapImage('imageName', '', 'newImage.jpg',1)" onMouseOut="MM_swapImgRestore()">
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Jul 8th, 2003, 01:48 PM
#3
wow...looks complicated....I have no time to look at it now. But when I have time I will test it out.
Thanks.
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