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Jimbob
Jul 19th, 2000, 04:10 AM
When I try to run this query: -
SELECT * FROM Staff WHERE ShowInList = 1 AND ShowInList2 = 1 ORDER BY Name ASC;
I get this error
3251: Object or provider is not capable of performing the requested operation
If I remove the ORDER BY part, I don't get any errors, so that's where I think the problem lies
The Name field is of VarChar type, but i have tried it as Char, NChar, NvarChar, Text and I can't get it to work.
any suggestions????
lenin
Jul 19th, 2000, 04:18 AM
Hi JimBob,
are you running this SQL from VB or on SQL Server. I looks fine to me. What happens if you selet * and order without any where clause?
Lenin
Jimbob
Jul 19th, 2000, 04:22 AM
i'm running the query from vb
if i run the query in enterprise manager, it all works loveley and nice wonderful etc
if i remove the WHERE bit, it won't work.
lenin
Jul 19th, 2000, 04:30 AM
Ok, I'll have a go at it here and let you know.
Lenin
Jimbob
Jul 19th, 2000, 04:35 AM
ooh, you are wonderful!
lenin
Jul 19th, 2000, 04:45 AM
I just did the following against a small table I have in SQL Server.
The table looks like this
num queryStatus
----------- --------------------
1 Open
2 Closed
3 Pending Analyst
4 Pending Customer
5 Development
Private Sub Command1_Click()
Dim lc_command As New ADODB.Command
Dim lconn As New ADODB.Connection
Dim lrs_records As New ADODB.Recordset
Dim ls_records As String
lconn.Open "DSN=class"
lc_command.CommandText = "select * from query_status where num < 5 order by querystatus"
lc_command.CommandType = adCmdText
lc_command.ActiveConnection = lconn
Set lrs_records = lc_command.Execute
lrs_records.MoveFirst
Do Until lrs_records.EOF
ls_records = ls_records & vbCrLf & lrs_records!querystatus
lrs_records.MoveNext
Loop
Debug.Print ls_records
End Sub
This doesn't error out, and gives the following:
Closed
Open
Pending Analyst
Pending Customer
Thanks
Lenin
Clunietp
Jul 19th, 2000, 10:55 AM
NAME might be a reserved SQL Server keyword. Try this SQL instead:
SELECT * FROM Staff WHERE ShowInList = 1 AND ShowInList2 = 1 ORDER BY [Name] ASC;
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