Log Problem

[SilverSprite]

Solve for x.http://vbforums.com/attachment.php?s=&postid=1168554

[SteveCRM]

11/6

http://www.galah.net/forums/images/smilies/thumb.gif

[SilverSprite]

I'm sorry but that answer is wrong. At least I think. Havent done it in some time. Let me check!

[SteveCRM]

im sticking by my answer ;) http://www.galah.net/forums/images/smilies/thumb.gif

[SteveCRM]

the suspense is killing me :eek:

[SilverSprite]

Log4 (8*cubert(32)) - Log4 (2)
=Log4 (8*cubert(32)) - 1/2
=Log4 (8) + Log4 (cubert(32)) - 1/2
=Log2 (8)/Log2 (4) +Log4 (cubert(32)) -1/2
=3/2 - 1/2 + Log4 (cubert(32))
=2/2 + Log4 2(cubert(4))
=1 + Log4 (2) + Log4 (4)/3
=1 + 1/2 + 1/3
=6/6 + 3/6 + 2/6
=11/6

Oh nice good job steve!

[SteveCRM]

*bows* :p

[SilverSprite]

Lol guess my memory fails me! Again, it wouldnt be the first time. Try the other ones i have up! http://vbforums.com/showthread.php?s=&threadid=198278

[SteveCRM]

I figured multiplication, I thought that was part of the radical bar, thats how I write mine..

[SilverSprite]

it was multiplication

[SilverSprite]

4^x=4*(32)^(1/3)

4^x=2*4*4^(1/3)

I think you missed a 4.
Wouldnt it be:

4^x=4*(32)^(1/3)

4^x=4*(2*4*4)^(1/3)?

Tell me if i'm wrong?

[bugzpodder]

sure ur right but so am i

[SilverSprite]

?

[bugzpodder]

you are correct but so am i

4^x=4*(2*4*4)^(1/3)

is correct

[SilverSprite]

Guess what bugz! Your confusing me again!

[bugzpodder]

4^x=4*(32)^(1/3)

4^x=4*(23*4)^(1/3)
4^x=2*4*(4)^(1/3)

[SilverSprite]

I still dont see where the 4 went?

[bugzpodder]

what 4?

[SilverSprite]

actually nm your right bugz