The line
produces an error, but I can't figure out why... This is part of a larger sub, but I don't want to bore you guys with thatVB Code:
textlocation = InStr(start, text, test, vbTextCompare)![]()
Does anyone know why this is giving an error??
VB Code:
'declarations' Dim dbase As Database Dim recset As Recordset Dim length As Integer Dim str As String Dim htmltag As String Dim str2 As String Dim result As String Dim textlocation As Long Dim start As Integer Dim endlocation As Long Set dbase = OpenDatabase(dblocation) start = 0 Do 'look for the space and replace with   tag' test = Chr(32) textlocation = InStr(start, text, test, vbTextCompare) start = textlocation 'exit the do in case of nothing found. The 0 value would cause errors in the subsequent lines' If textlocation = 0 Then Exit Do End If 'read the part before the space, the -1 ensures the space itself is not read' str = Mid(text, 1, (textlocation - 1)) 'read the part after the space, the +1 ensures the space itself is not read' str2 = Mid(text, (textlocation + 1)) 'insert the space tag in between' text = str & "   " & str2 Loop Until textlocation = 0




??
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