Array with 0 index?

[DeepBlueCode]

I have an array tha has the number of indexes as a variable. It is possible that the variable could be 0 (arrExam[0]). What would this do?

[CornedBee]

array indices always start with 0. ar[0] would access the first element in the array.

[DeepBlueCode]

What I meant was in the declaration of the array. If I declared it with 0 subsections...

[jim mcnamara]

int ar[0];

is the same thing as

int ar;

Both are just fine.

If you want variable length arrays you adoing the hard way.
Just use pointers -

int *ar; -- this lets you have any number of elements.

int *ar, *ar_base;

ar=(*int) malloc(100);
ar_base = ar;

ar_base is the first element, you can get any other element by addition ie., element # 5 is: ar = ar_base + 5;

[Wynd]

Or you could do:

int* ar; // Lets you have any number of ints

ar = new int[100]; // 100 ints, you can use a variable in place of
                   // 100 if you don't know how many you'll need

delete[] ar; // Frees up memory at the end of program 

The to get the 5th element, just do:

cout << ar[4] << endl; // Just like normal arrays 

[kedaman]

Originally posted by jim mcnamara
int ar[0];

The smallest array you can allocate is 1

[MoMad]

Use if statement to allocate a single int and then in the delete use if statement again to deallocate that single int!