C++ Functions

[Dillinger4]

Does anyone know how i can have a funcion return a string?
char wintest(int x1,int y)
{
if ((count1==1)||(count1 == 3) || (count1 == 5) || (count1 ==7) || (count1 == 9))
return win;
}


// this is declared before the main
char win []= {
"Player 1 is the winner",
};

so as far as i can tell win should hold the string but char only returns one character. so basically im stuck. any suggestions?
thanxxxxx

You can do the following
#include<string> //if you are using VC++

using namespace std

string something()
{
return "Hello everyone.";
}

int main(int argc,char *argv[])
{
string ret;
ret=something;
cout << ret.c_str();
return 0;
}

or return a character pointer#include<fstream.h>

char * hi()
{
char * ret;
ret="hi";
return ret;
}

void main()
{
char * ret;
ret=hi();
cout << ret;
}

[rchiav]

Do this..

//char wintest(int x1,int y)
//make the function return a pointer to a string.
char * wintest(int x1, int y)
{
if ((count1==1)||(count1 == 3) || (count1 == 5) || (count1 ==7) || (count1 == 9))
return win;
}


// this is declared before the main
//char win []= {
//"Player 1 is the winner",
//};
//create a pointer to the string...
char *win = "Player 1 is the winner";

The problem is that the function is declared as a char.. that's not a string. That's one character. Your array "win" is kind of creating a pointer.. so saying that you want to return "win" is actually saying "return win[0]". win is actually a pointer to the first element in the array. You really want to return a pointer to the array, or you're going to want to use strcpy (better to use strncpy) to copy the text to where you want it. All depends on what you want to do.