Path of a projectile

[MXK]

I have a projectile starting at a certain location. I know the original x and y, the initial power, gravity, and also the wind speed. I need to be able to plot a point where the projectile is going to be at a certain time taking into the account all of these values. Technically I found the two equations that should be used, but for some reason instead of going in an arch the projectile goes in a curve upward from the origin. I've checked all the values and they are all accurate. Can someone give these two equations and explain them? Thanks.

[MXK]

Right, should have specified that. I have the initial velocity not power. Air drag would be nice (I would be specifying how much, or what the altitude is), but it's not necessary.

[DavidHooper]

I remember this from mechanics lessons:

y = xtanT - (0.5 g x^2) / (V^2 cos^2(T))

y is vertical co-ord.
x is horizontal co-ord.
T is launch angle.
V is launch speed.
g is gravity.

That's if memory serves correctly ;) This takes no account of wind speed although you can add it in if you go back to the s=ut+0.5at^2 and put in a wind term. Post again if you're stuck.

[Guv]

It seem to me that the equations are something like the following.Distance = InitialDistance + Velocity*Time*Cosine(LaunchAngle)

Height = InitialHeight + Velocity*Time*Sine(LaunchAngle) - GravityAcceleration*Time^2 / 2If the above are not correct, they are close to the correct equations. When not paid with money or sexual favors, I do not verify my memory versus some of the books I have.

If Velocity is a function of time (and maybe itself) due to air resistance, then you can plug it into the above.