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sail3005
Sep 18th, 2001, 09:40 PM
Find equation of quadratic function:
it's graph is a parabola with x-intercepts 2 and -1 and y-intercept 6.
Please, i really need help on this!!!
nishantp
Sep 18th, 2001, 09:45 PM
I dont know jack about quaderatic equations myself, but Kaverin posted a functionn that might help:
here (http://www.vbforums.com/showthread.php?s=&threadid=103342)
Bjwbell
Sep 19th, 2001, 01:59 AM
I'ts easy just setup three equations
6=a*0^2 + b*0 +m
m=6
0=a*2^2+b*2+6
0=a*(-1)^2+b*-1+6
solve for a and b
a=-3
b=3
so
y=-3x^2+3x+6
sail3005
Sep 19th, 2001, 05:12 PM
thanks that helped a lot
Bjwbell
Sep 19th, 2001, 08:00 PM
Wow! i helped someone:)
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